Is the following relation a function? (4,2), (1,1), (0,0), (1, -1), (4, -2). Give the domain and range.

1 answer:

8 0

(x,y)
to be a function
for every x, ther must be only 1 y to corespond to it
basically, x must NEVER repeat with a different y
list them

ah, we see (1,1) an d(1,-1)
also (4,2) and (4,-2)
double offense
1 repeats with 1 and -1
4 repeats with 2 and -2

not a function

domain is all x values
range is all y values
if they repeat, don't list them

domain=(0,1,4)
range=(-2,-1,0,1,2)

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Help ASAP!!<br>Using the graphed function above, find the following

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Answer:

Maximum: 1, Minimum: -3, Midline y = -1, Amplitude = 4, Period = $\pi$ , Frequency $\displaystyle =\frac{1}{\pi}$ , equation : $f(x)=-4cos(2x)+1$

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<u>Sinusoid Functions</u>

It refers to the oscillating functions like the sine or cosine which range from a minimum and maximum value periodically.

The graph shown can give us all the information we need to answer these questions:

Maximum: 1

Minimum: -3

The midline goes through the center value (mean) of the max and min values, i.e.

Equation of the midline:

$\displaystyle y=\frac{1-3}{2}=-1$

Amplitude is the difference between the maximum and minimum values

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The period is the time it takes to complete a cycle. We can see the minimum value is first reached at x=0 and next at $x=\pi$

Thus the period is

$T=\pi$

The frequency is the reciprocal of the period:

$\displaystyle f=\frac{1}{T}=\frac{1}{\pi}$

The angular frequency is

$\displaystyle w=2\pi f=\frac{2\pi }{\pi}=2$

The equation of the function is a negative cosine (since it starts at the minimum) or a shifted sine or cosine. We'll choose the negative cosine, knowing all the parameters:

$f(x)=-4cos(2x)+1$

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Mara writes the expression x + 2(x – 4) – 4x. Which of these expressions are equivalent? Choose the

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it is number 1. because the answer above is equivalent to number 1