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dimaraw [331]
3 years ago
11

Student Weight of Backpack Amir 20,100 g Betty 19.2 kg Sandro 21,300 g Lea 20,120 g Maurizio 19.8 kg Students in Ms. Victoria’s

class have backpacks of different weights, as shown in the table. Which student’s backpack is the heaviest?
Mathematics
1 answer:
Lunna [17]3 years ago
8 0

Hey there!

First, we should make sure all of these weights are in the same unit of measurement. Let's convert all the grams to kilograms.

In kilograms, we already have these students:

  • Betty, 19.2 kg
  • Maurizio, 19.8 kg

There are 1,000 grams in a kilogram, so divide the amount of grams by 1,000 to convert to kilograms.

20,100 ÷ 1,000 = 20.1 (Amir)

21,300 ÷ 1,000 = 21.3 (Sandro)

20,120 ÷ 1,000 = 20.12 (Lea)

So now we have (ordered from greatest to least):

  • 21.3 kg (Sandro)
  • 20.12 kg (Lea)
  • 20.1 kg (Amir)
  • 19.8 kg (Maurizio)
  • 19.2 kg (Betty)

<u>The student with the heaviest backpack is Sandro, with a backpack of 21.3 kg.</u>

Hope this helps!

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Simplify expression x8y-26/x14y-5 × x-39y-21
koban [17]

The simplified form of the expression is x^{-45} y^{-42}

<h3>Simplifying an expression</h3>

From the question, we are to simplify the given expression

The given expression is

\frac{x^{8}y^{-26}  }{x^{14}y^{-5}  } \times x^{-39} y^{-21}

The expression can be simplified as shown below

\frac{x^{8}y^{-26}  }{x^{14}y^{-5}  } \times x^{-39} y^{-21}

\frac{x^{8} \times x^{-39} \times  y^{-26} \times  y^{-21}  }{x^{14} \times y^{-5}  }

\frac{x^{8+-39} \times  y^{-26+-21}  }{x^{14} \times y^{-5}  }

\frac{x^{8-39} \times  y^{-26-21}  }{x^{14} \times y^{-5}  }

\frac{x^{-31} \times  y^{-47}  }{x^{14} \times y^{-5}  }

Then,

\frac{x^{-31} }{x^{14} } \times \frac{ y^{-47} }{ y^{-5} }

x^{-31-14} \times y^{-47--5}

x^{-31-14} \times y^{-47+5}

x^{-45} \times y^{-42}

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Hence, the simplified form of the expression is x^{-45} y^{-42}

Learn more on Simplifying an expression here: brainly.com/question/2320607

#SPJ1

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Answer:

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Step-by-step explanation:

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