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klio [65]
3 years ago
11

What is 2x+3=x-4 I really need help on this question​

Mathematics
2 answers:
Vesna [10]3 years ago
8 0

Subtract x from both sides

2x + 3 - x = -4

Simplify 2x + 3 - x to x + 3

x + 3 = -4

Subtract 3 from both sides

x = -4 - 3

Simplify -4 - 3 to -7

<u>x = -7</u>

mariarad [96]3 years ago
4 0

2x+3=x-4

2x-x= -4-3

x= -7

Check answer by using substitution method

2(-7)+3= -7-4

-14+3=-11

-11=-11

Answer is x=-7

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erik [133]
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6 0
3 years ago
Drex's and Max's ages add up to 29.Seven years ago Drex was twice as old as Max. Find their present ages​
nexus9112 [7]

Answer:

There present ages are

Drex age = 17 years

Max age  =  12 years

Step-by-step explanation:

Given as ,

The sum of age of Drex and Max = 29 years

And seven years ago Drex was twice as old as max

So , Let the Age of Drex = D   and Max age = M

I.e (D - 7 ) = 2 (M - 7)

Or, D - 7 = 2M - 14

Or, 2M - D = 7

And Also D + M = 29  

So , from both equations

(2M - D ) + (D + M) = 29 +7

Or,  3M = 36

I.e M = \frac{36}{3} = 12 years

∴ The Age of Drex = 29 - M

  The Age of Drex = 29 - 12 = 17 years

Hence there present ages are

The Age of Drex = 17 years

The Age of Max = 12 years     Answer

6 0
3 years ago
The predicted cost c (in hundreds of thousands of dollars) for a company to remove p% of a chemical from its waste water is show
alukav5142 [94]
We presume your cost function is
  c(p) = 124p/((10 +p)(100 -p))

This can be rewritten as
  c(p) = (124/11)*(10/(100 -p) -1/(10 +p))

The average value of this function over the interval [50, 55] is given by the integral
  \frac{1}{55-50} \times \frac{-124}{11} \int\limits^{55}_{50} {(\frac{1}{x+10}+\frac{10}{x-100})} \, dx
This evaluates to
  (-124/55)*(ln(65/60)+10ln(45/50)) ≈ 2.19494

The average cost of removal of 50-55% of pollutants is about
  $2.19 hundred thousand = $219,000

8 0
4 years ago
Which angles are adjacent angles to 3? Select all that apply
sattari [20]

Two Answers: Angle 1, Angle 4

Adjacent angles share a common segment, line, or ray. Think of two adjacent rooms sharing a common wall.

3 0
3 years ago
Verify the identity by transforming the left-hand side into the right-hand side.
qaws [65]
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1

Starting with the left:  Note that  cos²θ + </span><span>sin²θ = 1.
In the same way:    </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore                cos²3θ  = 1 - <span>sin²3θ
</span> From the top:  (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ

=  2/<span>sin² 3θ - 1;        But 1/</span><span>sinθ = csc</span><span>θ,  Similarly  </span>1/sin3θ = csc3θ

= 2 *(1/sin<span>3θ)²  - 1</span>
= 2csc²3θ  - 1.        Therefore  LHS = RHS.  QED.

8 0
3 years ago
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