Answer:
There present ages are
Drex age = 17 years
Max age = 12 years
Step-by-step explanation:
Given as ,
The sum of age of Drex and Max = 29 years
And seven years ago Drex was twice as old as max
So , Let the Age of Drex = D and Max age = M
I.e (D - 7 ) = 2 (M - 7)
Or, D - 7 = 2M - 14
Or, 2M - D = 7
And Also D + M = 29
So , from both equations
(2M - D ) + (D + M) = 29 +7
Or, 3M = 36
I.e M =
= 12 years
∴ The Age of Drex = 29 - M
The Age of Drex = 29 - 12 = 17 years
Hence there present ages are
The Age of Drex = 17 years
The Age of Max = 12 years Answer
We presume your cost function is
c(p) = 124p/((10 +p)(100 -p))
This can be rewritten as
c(p) = (124/11)*(10/(100 -p) -1/(10 +p))
The average value of this function over the interval [50, 55] is given by the integral

This evaluates to
(-124/55)*(ln(65/60)+10ln(45/50)) ≈ 2.19494
The average cost of removal of 50-55% of pollutants is about
$2.19 hundred thousand = $219,000
Two Answers: Angle 1, Angle 4
Adjacent angles share a common segment, line, or ray. Think of two adjacent rooms sharing a common wall.
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1
Starting with the left: Note that cos²θ + </span><span>sin²θ = 1.
In the same way: </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore cos²3θ = 1 - <span>sin²3θ
</span> From the top: (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ
= 2/<span>sin² 3θ - 1; But 1/</span><span>sinθ = csc</span><span>θ, Similarly </span>1/sin3θ = csc3θ
= 2 *(1/sin<span>3θ)² - 1</span>
= 2csc²3θ - 1. Therefore LHS = RHS. QED.