120º is 1/3 of a complete revolution of 360º. So the area of this sector should be 1/3 the area of the complete circle.
A circle with radius 9 has area 9^2 π = 81π.
So the sector has area 81π/3.
Put another way: The area <em>A</em> of a circular sector and its central angle <em>θ</em> (in degrees) occur in the same ratio as the area of the entire circle with radius <em>r</em> according to
<em>A</em> / <em>θ </em>º = (π <em>r </em>^2) / 360º
==> <em>A</em> = π/360 <em>θ r</em> ^2
In this case, <em>r</em> = 9 and <em>θ</em> = 120º, so
<em>A</em> = π/360 * 120 * 81 = 81π/3
Answer:
2π
Step-by-step explanation:
Area = πr^2
= π2^2
= 4π
4π is the area of the whole circle, so divide it in half to get the semicircle.
<u>= 2π</u>
-- If two lines on a graph are parallel, then their slopes are equal.
-- If two lines on a graph are perpendicular, then their slopes are
negative reciprocals.
Numerical, subtraction, s
