Question

Help pls................

Answer 1

Answer:

x = - 10, x = 10

Step-by-step explanation:

Given

- 7 + $(x^2-19)^{\frac{3}{4} }$ = 20 ( add 7 to both sides )

$(x^2-19)^{\frac{3}{4} }$ = 27 , that is

$\sqrt[4]{(x^2-19)^{3} }$ = 27 ( raise both sides to the power of 4 )

(x² - 19)³ = $27^{4}$ = 531441 ( take the cube root of both sides )

x² - 19 = $\sqrt[3]{531441}$ = 81 ( add 19 to both sides )

x² = 100 ( take the square root of both sides )

x = ± $\sqrt{100}$ = ± 10

solution is x = - 10, x = 10

Answer 2

Hai!!! Your answer is both x=-10 and x=10