Answer:
≈ 0.52
Step-by-step explanation:
P( head ) = 2/3 , P( tail ) = 1/3
when a head is tossed ; Gambler A wins $1
when a tail is tossed : Gambler B wins $1
<u>Determine the P( Gambler A wins the game ) if he starts with I dollars</u>
Assuming I = $1
n = 5
p ( head ) = P( winning ) = 0.66
p( losing ) = 0.33
applying the conditional probability in Markov which is ;
Pₓ = pPₓ₊₁ + (1 - p) Pₓ₋₁
P( 1) = 0.66P₂ + 0.33P₀
resolving the above using with Markov probability
P( 1 ) = 0.51613
hence the probability of Gambler A winning the game if he starts with $1
≈ 0.52
For the first one:tick the second to last.
for the second: tick the first circle.
for the third: tick the second to last.
for the forth: tick the second.
for the fifth: tick the last.
for the last one: tick the second.
Hope it helps...
<span>Exponential decay are; the domain is all real numbers, the base must be less than 1 and greater than 0 and the function has a constant multiplicative rate of change. The answers are letters A, D and E. An example is w</span>hen there are 70000 bacteria
present in a culture and reduced by half every four hours, the number of
bacteria will decrease. The bacteria will experience an exponential decay
because it decreases its number at a constant decay.
Answer: d. 0.55
Step-by-step explanation:
The given probability distribution:
Number of Goals 0 1 2 3 4
Probability .05 .15 .35 .30 .15
The probability that in a given game the Lions will score less than 3 goals
= probability that in a given game the Lions will score less than or equal to 2
= 0.5+0.15+0.35
= 0.55
Hence, the correct option is d. 0.55
Answer:
are those fractions or division signs
Step-by-step explanation:
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