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Jlenok [28]
3 years ago
14

What is m% of p% of n? MY LAZY BUTT DON'T WANNA DO THIS

Mathematics
1 answer:
Len [333]3 years ago
3 0
M% of p% of n
m/100 · p/100 · n.
You might be interested in
Please help!
lana [24]

Given Information:

Principle amount = P = $6,000

Interest rate = r = 4% = 0.04

Period in years = t = 5

Required Information:

How much interest will he earn in 5 years = ?

Answer:

Amount of interest = $1,299.92

Step-by-step explanation:

Using the formula given in the question,

B = P(1 + r )^{t}

Where B is the final amount, P is the initial amount, r is the interest rate and t is the number of years

B = P(1 + r )^{t}\\\\B = 6,000(1 +  0.04)^{5}\\\\B = 7,299.92

The amount of interest earned is

Amount \:of\: interest = B - P \\\\Amount \:of \:interest = 7,299.92 - 6,000\\\\Amount \:of \:interest = 1,299.92

Therefore, Quincy has earned $1,299.92 in terms of interest by investing  $6,000 in a savings account at the rate of 4% annual interest for a period of 5 years.

6 0
3 years ago
The distance between two towns on a map is 9 centimeters. the actual distance between two towns is 63 kilometers. what is the sc
Ilia_Sergeevich [38]
If your trying to find the unit rate or the scale of the map, you need to figure out how many kilometers are per centimeters. To get that you need to do 63 divided by 9, witch would get you 7. So to my ability, the answer would be 1 cm per 7 kilometers. Hopefully this answer helped you and I'm hoping its correct.
5 0
3 years ago
Read 2 more answers
A fossil was analyzed and determined to have a carbon-14 level that is 80 % that of living organisms. the half-life of c-14 is 5
liq [111]

Answer:

The fossil is 1860 years old.

Step-by-step explanation:

The equation for the amount of fossil has the following format:

Q(t) = Q(0)e^{rt}

In which Q(t) is the amount after t years, Q(0) is the initial amount and r is the rate of change.

Half-life of c-14 is 5730 years.

This means that Q(5730) = 0.5Q(0)

So

Q(t) = Q(0)e^{rt}

0.5Q(0) = Q(0)e^{5730r}

e^{5730r} = 0.5

\ln{e^{5730r}} = \ln{0.5}

5730r = \ln{0.5}

r = \frac{\ln{0.5}}{5730}

r = -0.00012

So

Q(t) = Q(0)e^{-0.00012t}

How old is the fossil?

This is t for which

Q(t) = 0.8Q(0)

So

Q(t) = Q(0)e^{-0.00012t}

0.8Q(0) = Q(0)e^{-0.00012t}

e^{-0.00012t} = 0.8

\ln{e^{-0.00012t}} = \ln{0.8}

-0.00012t = \ln{0.8}

t = -\frac{\ln{0.8}}{-0.00012}

t = 1860

The fossil is 1860 years old.

4 0
3 years ago
Which expression is equivalent to 1/3y?
Fittoniya [83]

Equivalent expression

y/3   = 1/3 * y

4 0
3 years ago
Read 2 more answers
Evaluate ( 4 upon 3 ) -2<br><br><br>please amswer fast​
Taya2010 [7]
<h2><u>Solution</u></h2>

\frac{4}{3}  - 2 \\  \\   = \frac{4 - 6}{ 3}  \\  \\  =  \frac{ - 2}{3}

<h3>Hope This Helps You ❤️</h3>
6 0
3 years ago
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