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lisabon 2012 [21]
3 years ago
6

In an inelastic collision involving an isolated system, the final total momentum isA) more than the initial momentum.B) exactly

the same as the initial momentum.C) less than the initial momentum.
Physics
1 answer:
damaskus [11]3 years ago
5 0

I think that the answer is C

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A series LRC circuit consists of a 12.0-mH inductor, a 15.0-µF capacitor, a resistor, and a 110-V (rms) ac voltage source. If th
finlep [7]

Answer:

61.85 ohm

Explanation:

L = 12 m H = 12 x 10^-3 H, C = 15 x 10^-6 F, Vrms = 110 V, R = 45 ohm

Let ω0 be the resonant frequency.

\omega _{0}=\frac{1}{\sqrt{LC}}

\omega _{0}=\frac{1}{\sqrt{12\times 10^{-3}\times 15\times 10^{-6}}}

ω0 = 2357 rad/s

ω = 2 x 2357 = 4714 rad/s

XL = ω L = 4714 x 12 x 10^-3 = 56.57 ohm

Xc = 1 / ω C = 1 / (4714 x 15 x 10^-6) = 14.14 ohm

Impedance, Z = \sqrt{R^{2}+\left ( XL - Xc \right )^{2}}

Z = \sqrt{45^{2}+\left ( 56.57-14.14 )^{2}} = 61.85 ohm

Thus, the impedance at double the resonant frequency is 61.85 ohm.

7 0
3 years ago
Which of the following is the suffix that means “berry shaped?"
Ipatiy [6.2K]

Answer:

Coccus

Explanation:

Berry shaped bacterium. Streptococci. Berry shaped bacteria occurring in twisted chains

7 0
3 years ago
a child hits a ball with a force of 350 N. (a) If the ball and bat are in contact for 0.12 is, what impulse does the ball receiv
Lina20 [59]

Explanation:

Given that,

Force with which a child hits a ball is 350 N

Time of contact is 0.12 s

We need to find the impulse received by the ball. The impulse delivered is given by :

J=F\times t\\\\J=350\times 0.12\\\\J=42\ N-m

So, the impulse is 42 N-m..

We know that he change in momentum is also equal to the impulse delivered.

So, impulse = 42 N-m and change in momentum =42 N-m.

7 0
4 years ago
A small artery has a length of 1.10 × 10-3 m and a radius of 2.50 × 10-5 m. If the pressure drop across the artery is 1.15 kPa,
levacccp [35]

Answer:

7.69533\times 10^{-11}\ m^3/s

Explanation:

P = Pressure difference = 1.15 kPa

r = Radius = 2.5\times 10^{-5}\ m

\eta = Viscosity of liquid = 2.084\times 10^{-3}\ Pas

l = Length of artery = 1.1\times 10^{-3}\ m

From Poiseuille's equation we have

Q=\frac{\pi Pr^4}{8\eta l}\\\Rightarrow Q=\frac{\pi 1.15\times 10^3\times (2.5\times 10^{-5})^4}{8\times 2.084\times 10^{-3}\times 1.1\times 10^{-3}}\\\Rightarrow Q=7.69533\times 10^{-11}\ m^3/s

The flow rate of blood is 7.69533\times 10^{-11}\ m^3/s

8 0
3 years ago
Q7 Describe two types of atomic change that produce electromagnetic<br> waves.
Crank
When a neutron or a proton in the nucleus changes a gamma ray is produced (gamma rays are electromagnetic waves)

When an electron drops from a higher energy level to a lower energy level an electromagnetic wave is give off.
7 0
3 years ago
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