In an inelastic collision involving an isolated system, the final total momentum isA) more than the initial momentum.B) exactly
1 answer:
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Answer:
D = 43 m
Explanation:
given,
initial velocity = 18 m/s
angle θ = 60°
total horizontal distance covered by the shell is
applying conservation of momentum in horizontal direction
m v₀ cos θ = m₁v₁ + m₂ v₂
m v₀ cos θ = 0.5 m v₂
v₂ = 2 v₀ cos θ.
distance covered by the shell from point of explosion
R' = v t
=
=
=
= R
total distance traveled by the shell is
D =
= 1.5 R
=
D =
= 42.9 ≅ 43 m
D = 43 m