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Lynna [10]
3 years ago
8

A single slit forms a diffraction pattern, with the first minimum at an angle of 40.0° from central maximum, when monochromatic

light of 630-nm wavelength is used. The same slit, illuminated by a new monochromatic light source, produces a diffraction pattern with the second minimum at a 60.0° angle from the central maximum. What is the wavelength of this new light?
Physics
1 answer:
Margarita [4]3 years ago
3 0

Answer:

\lambda = 424.4 nm

Explanation:

As we know by the formula of diffraction

a sin\theta = N\lambda

so we have

a = slit size

\theta = angular position of Nth minimum

so we will have

for first minimum of 630 nm light

a sin40 = 1(630 \times 10^{-9})

a = 9.8 \times 10^{-7} m

Now for another wavelength second minimum is at 60 degree angle

a sin60 = 2 \lambda

(9.8 \times 10^{-7}) sin60 = 2 \lambda

\lambda = 424.4 nm

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