Explanation:
hope it's help you ok have a good day
Machines makes work easier by increasing the amount of force that is applied, and changing the direction in which the force is applied !! Hope it helped (p.s. I had this same question)
Answer:
T₂ =602 °C
Explanation:
Given that
T₁ = 227°C =227+273 K
T₁ =500 k
Gauge pressure at condition 1 given = 100 KPa
The absolute pressure at condition 1 will be
P₁ = 100 + 100 KPa
P₁ =200 KPa
Gauge pressure at condition 2 given = 250 KPa
The absolute pressure at condition 2 will be
P₂ = 250 + 100 KPa
P₂ =350 KPa
The temperature at condition 2 = T₂
We know that
![\dfrac{T_2}{T_1}=\dfrac{P_2}{P_1}\\T_2=T_1\times \dfrac{P_2}{P_1}\\T_2=500\times \dfrac{350}{200}\ K\\](https://tex.z-dn.net/?f=%5Cdfrac%7BT_2%7D%7BT_1%7D%3D%5Cdfrac%7BP_2%7D%7BP_1%7D%5C%5CT_2%3DT_1%5Ctimes%20%5Cdfrac%7BP_2%7D%7BP_1%7D%5C%5CT_2%3D500%5Ctimes%20%5Cdfrac%7B350%7D%7B200%7D%5C%20K%5C%5C)
T₂ = 875 K
T₂ =875- 273 °C
T₂ =602 °C
Answer to A spring<span> is </span>stretched<span> to a </span>displacement<span> of </span>3.4 m<span> from </span>equilibrium<span>. </span>Then<span> the </span>spring<span> is</span>released<span> and ... </span>Then<span> the </span>spring<span> is </span>released<span> and </span>allowed<span> to </span>recoil<span> to a </span>displacement<span> of </span>1.9 m<span> from</span>equilibrium<span>. The </span>spring constant<span> is </span>11 N/m<span>. What </span>best describes<span> the </span>work involved<span> as the </span>spring recoils<span>? A)87 J of </span>work<span> is performed ...</span>
Answer:
350 F to 100 F it take approx 87.33 min
Explanation:
given data
oven = 350◦F
cooling rack = 70◦F
time = 30 min
cake = 200◦F
solution
we apply here Newtons law of cooling
= -k(T-Ta)
=
(T(t) -Ta)
=
= -k(T-Ta)
-ky
= -ky
T(t) -Ta = (To -Ta)
T(t) = Ta+ (To -Ta)
put her value for time 30 min and T(t) = 200◦F and To =350◦F and Ta = 70◦F
so here
200 = 70 + ( 350 - 70 ) ![e^{-k30}](https://tex.z-dn.net/?f=e%5E%7B-k30%7D)
k = 0.025575
so here for T(t) = 100F
100 = 70 + ( 350 - 70 ) ![e^{-0.025575*t}](https://tex.z-dn.net/?f=e%5E%7B-0.025575%2At%7D)
time = 87.33 min
so here 350 F to 100 F it take approx 87.33 min