This sounds pretty easy, in fact. The orbital motion can be assumed to be circular and with constant speed. Then, the period is the time to do one revolution. The distance is the length of a revolution. That is 2*pi*R, where R is the distance between the Moon and the Earth (the respective centers to be precise). In summary, it's like a simple motion with constant speed:
v = 2*pi*R/T,
you have R in m and T is days, which multiplied by 86,400 s/day gives T in seconds.
Then v = 2*pi*3.84*10^8/(27.3*86,400) = 1,022.9 m/s ~ 1 km/s (about 3 times the speed of sound :)
For the Earth around the Sun, it would be v = 2*pi*149.5*10^9/(365*86,400)~ 29.8 km/s!
I know it's not in the problem, but it's interesting to know how fast the Earth moves around the Sun! And yet we do not feel it (that's one of the reasons some ancient people thought crazy the Earth not being at the center, there would be such strong winds!)
Answer:
Explanation:
The velocity is 340, but the distance is not. Here's how you do this:
You need to find out the velocity of the that sound in that temp which has a formula of
v = 331.5 + .606T where T is the temp in Celcius. Filling in and using the correct number of sig dig:
v = 331.5 + .606(20) and
v = 331.5 + 10 and
v = 340 m/s. Now we need to use that in d = vt:
d = 340(2.00) so
d = 680 m
Answer:
0.694 m
Explanation:
Case 1 : When only mass of 2.82 kg is hanged from spring
m = mass hanged from the spring = 2.82 kg
x = stretch caused in the spring = 0.331 m
k = spring constant
Using equilibrium of force in vertical direction
Spring force = weight of the mass
k x = m g
k (0.331) = (2.82) (9.8)
k = 83.5 N/m
Case 2 : When both masses are hanged from spring
m = mass hanged from the spring = 3.09 + 2.82 = 5.91 kg
x = stretch caused in the spring = ?
k = spring constant = 83.5 N/m
Using equilibrium of force in vertical direction
Spring force = weight of the mass
k x = m g
(83.5) x = (5.91) (9.8)
x = 0.694 m
a friction force 10 N less than the applied force, a normal force equal to the gravtiational force
Time , Work, Horsepower
Explanation:
In General, Power is defined as rate of doing work in physics.
1.) By work and Time, we can calculate power as follows,
Power = Work done per unit Time
= Work done / time
2.) From Horsepower we can directly get the power.
Horsepower (hp) is a unit to measure the power, or the rate at which work is done, usually in the output of engines or motors. There are many types of horsepower. Two common ways of defining horsepower is being used today are the mechanical horsepower (or imperial horsepower), which is about 745.7 watts, and the metric horsepower, which is approximately 735.5 watts.