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Lelechka [254]
3 years ago
15

45 points! Please help me ASAP!

Mathematics
2 answers:
zlopas [31]3 years ago
8 0
2 times 10^4 means 2 with 4 zeroes after it or 20000
4 times 10^6=4 with 6 zeros after it or 400000

compare

20000 and 4000000
we can see that 4000000 is 200 times of 20000
therefor the answer is C

we can also do
(4 times 10^6)/(2 times 10^4)=4/2 times (10^6)/(10^4)=2 times 10^2=200


answer is C
velikii [3]3 years ago
5 0
Your answer is C because when you solve for 2 x 10^4 you get 20,000 and when you solve for 2 x 10^6 you get 4,000,000 and 4,000,000 is 200 times more than 20,000.
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Ross needs to have a procedure done, and since he is over 65 he is on Medicare. Medicare says that according to their plan the a
stepladder [879]
I think the answer would be B. 3,000
4 0
3 years ago
Read 2 more answers
Can someone help me with this​
SashulF [63]

Answer:

\angle NRQ =85 \degree

Given:

\angle RPQ = 45 \degree \\  \angle PQR = (6x + 4)\degree \\  \angle NRQ = (15x - 5)\degree

Step-by-step explanation:

Property used: <em>An exterior angle of a triangle is equal to the sum of the opposite int</em><em>e</em><em>rior angles.</em>

<em>=  >  \angle RPQ +  \angle PQR =  \angle NRQ \\  \\  =  > 45 \degree + (6x + 4)\degree = (15x - 5)\degree \\  \\  =  > 45\degree + 6x\degree + 4\degree = 15x\degree - 5\degree \\  \\  =  > 49\degree  + 5 \degree= 15x\degree - 6x\degree \\  \\  =  > 54\degree = 9x\degree \\  \\  =  > 9x\degree = 54\degree \\  \\  =  > x\degree =  (\frac{54}{9} )\degree \\  \\  =  > x\degree = 6\degree \\  \\ Putting \: value \: of \: x \: in \:  \angle NRQ  \\   \\  =  > \angle NRQ = (15x - 5)\degree \\  \\  =  >  \angle NRQ = (15 \times 6 - 5) \degree \\  \\  =  >  \angle NRQ =85 \degree</em>

4 0
2 years ago
At a carnival you win a prize if you get a heads, you must first choose a coin. There is a fair and a biased coin, while choosin
Marta_Voda [28]

Answer:

c. 0.3421

Step-by-step explanation:

The computation of the probability of selecting the biased coin is shown below:

The probability of any coin selected is 1 ÷ 2

The probability in the case when the biased coin chosen & wins 1 ÷ 2 (1 - 0.74)

And, the win probability is 1 ÷ 2  (1 - 0.74) + 1 ÷ 2  (1 - 0.5)

Now the probability of biased or win is

=  {1 ÷ 2 (1 - 0.74)} ÷ { 1 ÷ 2  (1 - 0.74) + 1 ÷ 2  (1 - 0.5)}

= 0.13 ÷ 0.38

= 0.3421

Hence, the correct option is c. 0.3421

5 0
3 years ago
A taxi company charges passengers $1.75 for a ride, no matter how long the ride is, and an additional $0.40 for each mile travel
lions [1.4K]
$2.4

 1.75+0.40x=2.7
-1.75            -1.75
-------------------------
            0.40x=0.95
            -------------
                  0.40
             X=2.375
7 0
3 years ago
At a farm, there are two huge pits for storing hay. 90 tons of hay is stored in the first pit, 75 tons in the second pit. Then,
Travka [436]

Answer:

63 tons

Step-by-step explanation:

The problem statement asks for the tons of hay removed from the first pit. It is convenient to let a variable (x) represent that amount. This is said to be 3 times the amount removed from the second pit, so that amount must be x/3.

The amount remaining in the first pit is 90-x.

The amount remaining in the second pit is 75 -x/3.

Since the first pit remaining amount is half the second pit remaining amount, we can write the equation ...

... 90 -x = (1/2)(75 -x/3)

... 180 -2x = 75 -x/3 . . . . multiply by 2

... 105 - 2x = -x/3 . . . . . . subtract 75

... 315 -6x = -x . . . . . . . . multiply by 3

... 315 = 5x . . . . . . . . . . . add 6x

... 63 = x . . . . . . . . . . . . . divide by 5

63 tons of hay were taken from the first pit.

_____

<em>Check</em>

After removing 63 tons from the first pit, there are 27 tons remaining. After removing 63/3 = 21 tons from the second pit, there are 54 tons remaining. 27 is half of 54, so the answer checks OK.

6 0
3 years ago
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