Which choice is not a factor of 52? a. 4 b. 26 c. 3 d. 13

2 answers:

8 0

A. 4 . . . Yes. 52/4 = 13

b. 26 . . . Yes. 52/26 = 2

<em>c. 3 . . . . No. 52/3 = 17 and 1/3</em>

d). 13 . . Yes. 52/13 = 4

Aleks [24]2 years ago

7 0

A. 4 Yes 52/4 = 13
b. 26 Yes 52/26 =2
c. 3 No 52/3 = 17.333
d. 13 Yes 52/13 = 4

3 is not a factor of 52, so c.

You might be interested in

PLEASE HELP ME!!!!!!!!

Delicious77 [7]

Angle θ between two vectors is given by, $\theta =cos^{-1}( \frac{u
 \cdot v}{|u||v|} )$ ; where $u \cdot 
v=-5(-4)+(-4)(-3)=20+12=32$ ; $|u|= \sqrt{ (-5)^{2} + (-4)^{2} } = 
\sqrt{25+16} = \sqrt{41}$ and $|v|=\sqrt{ (-4)^{2} + (-3)^{2} } = 
\sqrt{16+9} = \sqrt{25}=5$ .
Therefore, $\theta =cos^{-1}( \frac{32}{ 5\sqrt{41}} )=cos^{-1}0.9995=1.8^o$

3 0

3 years ago

What number must you add to complete the square?<br> x^2 + 2x = -1

Andru [333]

$\large\begin{array}{l} \textsf{You must add 1 to complete the square.}\\\\ \textsf{There is a very common special product: (square of a sum)}\\\\ \mathsf{(a+b)^2=a^2+2ab+b^2}\\\\\\ \textsf{Take the given equation:}\\\\ \mathsf{x^2+2x=-1\qquad(i)}\\\\\\ \textsf{The first term is a square (x squared)}\\\\ \textsf{The second term is a product of 2, x and 1.} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{We need to find a proper value for b, so that if we add it to}\\\textsf{the left side of the equation, we get a perfect square.}\\\\ \textsf{So,}\\\\ \begin{array}{cccccccccc} \mathsf{a^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{a}&\!\!\!\cdot\!\!\!&\mathsf{b}&\!\!\!+\!\!\!&\mathsf{b^2}&=\mathsf{(a+b)^2}\\\\ \mathsf{\downarrow}&&&\!\!\!\!\!&\downarrow&\!\!\!\!\!&\downarrow&&\downarrow\\\\ \mathsf{x^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{x}&\!\!\!\cdot\!\!\!&\mathsf{1}&\!\!\!+\!\!\!&\mathsf{1^2}&=\mathsf{(x+1)^2} \end{array}\\\\\\ \textsf{Just by comparing the expressions above, we can conclude that}\\\textsf{b must be equal to 1, so we get a perfect square:}\\\\ \mathsf{(x+1)^2=x^2+2x+1} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{Back to (i), adding 1 to both sides:}\\\\ \mathsf{x^2+2x+1=-1+1}\\\\ \boxed{\begin{array}{c} \mathsf{(x+1)^2=0} \end{array}} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{If you want to solve this equation for x, you will find}\\\\ \mathsf{x+1=0}\\\\ \mathsf{x=-1}\quad\longleftarrow\quad\textsf{(solution)} \end{array}$

If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248

$\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}$

6 0

2 years ago

Read 2 more answers

A group of 8 friends went to a movie matinee. They spent $20 on snacks . The total cost of their tickets and snacks was $76.

Andru [333]

8x would represent multiplying 8(people) times x(ticket cost) But you don't know how much the tickets cost per person so that's why it's x.

8x + 20 = 76
76-20=56
56÷8=7
x equals 7

5 0

2 years ago

Read 2 more answers

What is 763 thousandths in scientific notation?

irina1246 [14]

7.63 ^-10!!!!!!!!!!!!!!!!!!!!!!!!

4 0

2 years ago

HELP ME [QUESTION IN IMAGE AND NOT THAT HARD EITHER]

kondaur [170]

Answer:

Button #4. The last button. 8p = t.

Step-by-step explanation:

This is because there are 8 pieces of string, and p is equal to the length of one string, so one string times 8 is the total length of all the strings.

8 0

2 years ago

Read 2 more answers