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VladimirAG [237]
2 years ago
10

Answer the screenshot, please. (no links! PDFs are fine.)

Mathematics
1 answer:
Otrada [13]2 years ago
6 0

Answer:

Mode: 91

Median: 91

Mean: 107

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The law of cosines is used to find the measure of Z.
Shtirlitz [24]

Answer:

C. Z=51^{\circ}

Step-by-step explanation:

We have been given a triangle. We are asked to find the measure of angle Z using Law of cosines.

Law of cosines: c^2=a^2+b^2-2ab\cdot \text{cos}(C), where, a, b and c are sides opposite to angles A, B and C respectively.

Upon substituting our given values in law of cosines, we will get:

16^2=19^2+18^2-2(19)(18)\cdot \text{cos}(Z)

256=361+324-684\cdot \text{cos}(Z)

256=685-684\cdot \text{cos}(Z)

256-685=685-685-684\cdot \text{cos}(Z)

-429=-684\cdot \text{cos}(Z)

\frac{-429}{-684}=\frac{-684\cdot \text{cos}(Z)}{-684}

0.627192982456=\text{cos}(Z)

\text{cos}(Z)=0.627192982456

Now, we will use inverse cosine or arc-cos to solve for angle Z as:

Z=\text{cos}^{-1}(0.627192982456)

Z=51.1566718^{\circ}

Z\approx 51^{\circ}

Therefore, the measure of angle Z is approximately 51 degrees.

6 0
3 years ago
Read 2 more answers
A5cm x 11 cm rectangle sits inside a circle with radius of 12 cm.
never [62]

Answer:

397.16 cm²

Step-by-step explanation:

Area of the circle = πr²

3.14 * 144 = 452.16

452.16 - (11 x 5 ) = area shaded region

452.16 - 55 = 397.16

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

5 0
3 years ago
This app doesn’t know how to read a picture
SSSSS [86.1K]
It’s the 3rd one hopefully this helps
5 0
3 years ago
Given a and b are first quadrant angles, sin a=5/13 and cos b=3/5 evaluate sin (a-b)1) -33/652) 33/653) 63/65
bezimeni [28]

The correct option is -33/65.

The solution is given below:

5 0
1 year ago
3
Marianna [84]

Answer:

<h2><u><em>Two-thirds times one-eighth = Start Fraction 1 Over 12 End Fraction </em></u></h2><h2><u><em>Three-halves times 8 = 12</em></u></h2>

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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