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3 years ago

What is BC ? Enter your answer in the box.

Mathematics

1 answer:

stiks02 [169]3 years ago

5 0

Mathematically it would be 8 since BE=CE and CE=4.

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What can you add to get 18 but multiply to get 180

ratelena [41]

Answer:

Step-by-step explanation:

10 + 8 equals 18 and 10 by 8 equals 180

4 0

2 years ago

I get pretty confused with these types of questions ??

Evgen [1.6K]

this should help I have it step

5 0

3 years ago

Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x

Serggg [28]

I assume $C$ has counterclockwise orientation when viewed from above.

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

so we first compute the curl:

$\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k$

Then parameterize $S$ by

$\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k$

where the $z$ -component is obtained from

$1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v$

with $0\le u\le\dfrac\pi2$ and $0\le v\le\dfrac\pi2$ .

Take the normal vector to $S$ to be

$\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k$

Then the line integral is equal in value to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}$

6 0

3 years ago

The SAT is standardized to be normally distributed with a mean µ = 500 and a standard deviation σ = 100. What percentage of SAT

Aliun [14]

Answer:

34.134%

68.268%

Step-by-step explanation:

Given that:

Mean (m) = 500

Standard deviation (s) = 100

Percentage between 500 and 600

P(500 < x < 600)

P(x < 600) - P(x < 500)

Z = (x - m) / s

P(x < 600)

Z = (600 - 500) /100 = 1

P(x < 500)

Z = (500 - 500) / 500 = 0

P(Z< 1) - P(Z < 0)

0.84134 - 0.5

= 0.34134

= 0.34134 * 100%

= 34.134%

B.) Between 400 and 600

P(x < 400)

Z = (400 - 500) /100 = - 1

P(x < 600)

Z = (600 - 500) / 500 = 1

P(Z< 1 ) - P(Z < - 1)

0.84134 - 0.15866

= 0.68268

= 0.68268 * 100%

= 68.268%

8 0

2 years ago

You thought the balance in your checking account was $68 when you check your online account you realize that you forgot to recor

erma4kov [3.2K]

68-26 = 42 dollar check

3 0

3 years ago

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