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Sveta_85 [38]
3 years ago
6

Analyze the graphed function to find the local minimum and the local maximum for the given function. On a coordinate plane, a cu

rved line with minimum values of (0.6, negative 8) and (3.4, negative 8), and a maximum value of (2, 0), crosses the x-axis at (0, 0), (2, 0), and (4, 0), and crosses the y-axis at (0, 0). Which statements about the local maximums and minimums for the given function are true? Choose three options. Over the interval [1, 3], the local minimum is 0 Over the interval [2, 4], the local minimum is –8. Over the interval [3, 5], the local minimum is –8. Over the interval [1, 4], the local maximum is 0. Over the interval [3, 5], the local maximum is 0.
Mathematics
2 answers:
kozerog [31]3 years ago
8 0

Answer:

b

Step-by-step explanation:

Kisachek [45]3 years ago
7 0

Answer:

B C D

Step-by-step explanation:

I hope this is correct

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sdas [7]
\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
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\cfrac{2x}{x^2+2x-24}-\cfrac{x}{x^2-36}\quad 
\begin{cases}
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\begin{array}{llll}
\textit{thus our LCD is}\\
(x-6)(x+6)(x-4)
\end{array}
\\\\\\
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Bello you have a great day
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