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3 years ago

What is the place value of 5 in 5,678.321

2 answers:

3 0

5 is in the thousands place. 6 is in the hundreds place. 7 is in the tens place. 8 is in the ones place. 3 is in the tenths place. 2 is in the hundreths place. 1 is in the thousandths place.

horrorfan [7]3 years ago

3 0

In 5,678.321 the 5 is in the thousands place.

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Which side of A DEF is the longest?

Cloud [144]

Answer:

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Step-by-step explanation:

8 0

3 years ago

What was the median number of posts made?

mariarad [96]

Using it's concept, it is found that the median number of posts made was of 8.5.

<h3>What is the median of a data-set?</h3>

The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.

In this problem, the total number of observations is the sum of the frequencies, hence:

T = 1 + 0 + 3 + 1 + 2 + 1 + 1 + 2 + 3 + 5 + 9 = 28

Even number, hence the median is the <u>mean between the 14th and the 15th elements</u>, of the ordered set, hence:

M = (8 + 9)/2 = 8.5.

To remind, the ordered set is: {0, 1, 1, 1, ..., 8, 8, 8, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 10, 10, 10}

The median number of posts made was of 8.5.

You can learn more about the median at brainly.com/question/16103295

6 0

2 years ago

If the area of the rectangle below is 36 square yards, what is the length of the missing side? Don’t forget to include the unit

Vitek1552 [10]

Answer: wheres the picture

Step-by-step explanation:

5 0

3 years ago

A 9.85 m ladder is placed against a wall. The height to the top of the ladder is 5 m more than the distance between the wall and

Dafna1 [17]

Given:

Length of the ladder = 9.85 m

The height to the top of the ladder is 5 m more than the distance between the wall and the foot of the ladder.

To find:

The height to the top and the distance between the wall and the foot of the ladder.

Solution:

let x be the distance between the wall and the foot of the ladder. Then the height to the top of the ladder is (x+5).

Pythagoras theorem: In a right angle triangle,

$Hypotenuse^2=Base^2+Perpendicular^2$

In the given situation, hypotenuse is the length of ladder, i.e., 9.85 m. The base is x m and the height is (x+5) m.

Using the Pythagoras theorem, we get

$(9.85)^2=x^2+(x+5)^2$

$97.0225=x^2+x^2+10x+25$

$0=2x^2+10x+25-97.0225$

$0=2x^2+10x-72.0225$

Here, $a=2, b=10,c=-72.0225$ . Using the quadratic formula, we get

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-10\pm \sqrt{(10)^2-4(2)(-72.0225)}}{2(2)}$

$x=\dfrac{-10\pm \sqrt{676.18}}{4}$

Approximating the value, we get

$x=\dfrac{-10\pm 26}{4}$

$x=\dfrac{-10+26}{4},\dfrac{-10-26}{4}$

$x=\dfrac{16}{4},\dfrac{-36}{4}$

$x=4,-9$

Distance cannot be negative so $x\neq -9.$

Now we have $x=4$

$x+5=4+5$

$x+5=9$

Therefore, the base is 4 m and the height is 9 m.

5 0

3 years ago

OwOoWoOwO pls answer, sorry about the random burst im really bad at math

Nataly [62]

Answer:

0.46

Step-by-step explanation:

42.78/m = 93

=> m = 42.78/93

=> m = 0.46

Hope my answer helps :)

7 0

3 years ago

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