We need to convert this equation to slope-intercept form first.
We can do that by solving for y.
x - 5y = 15
<em><u>Add 5y to both sides.</u></em>
x = 5y + 15
<em><u>Subtract 15 from both sides.</u></em>
x - 15 = 5y
<em><u>Divide both sides by 5.</u></em>
y = 1/5x - 3
We now know the slope is 1/5.
The slope of the line perpendicular to the line with a slope of 1/5 is -5.
The slope of a perpendicular line is the negative reciprocal of the original slope.
Using a graphing calculator, we know the y-intercept of the line that is perpendicular to the original line must have a y-intercept of -6 to run through the points (-2, 5).
The equation of the new line is y = -5x - 6.
Determine whether each equation is a linear equation. ... –2x – 3 = y .... linear. 16. 4y. 2. + 9 = –4. SOLUTION: Since y is squared, the equationcannot be written in standard form.
Answer:
x = 9
Step-by-step explanation:
50+80+(6x-4)=180 (ANGLE SUM PROPERTY)
130 +(6x-4)=180
6x-4=180-130
6x-4=50
6x=50+4
x=54/6
x = 9
Answer:
x-intercept: (-7.5 , 0) y-intercept: (0 , 5.5)
Step-by-step explanation:
12.06
why? well 6 is the hundredths place and you go over 1 to the 2 which is less than 5 so u dont change it
