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3 years ago

Choose the correct simplification of the expression −6x^2(4x − 7x^2 − 2)

Mathematics

2 answers:

Digiron [165]3 years ago

5 0

Answer:

D. $42x^4-24x^3+12x^2$

Step-by-step explanation:

We are given that an expression

$-6x^2(4x-7x^2-2)$

We have to choose the correct simplification of the given expression.

Multiply each term of bracket with [txe[-6x^2[/tex]

$(-6x^2)(4x)+(6x^2)(7x^2)+(6x^2)(2)$

$-24x^3+42x^4+12x^2$

Hence, the simplification of the given expression is given by

$42x^4-24x^3+12x^2$

Answer:D. $42x^4-24x^3+12x^2$

insens350 [35]3 years ago

4 0

Answer:

Option D is the correct answer.

Step-by-step explanation:

The given expression is :

$-6x^{2} (4x-7x^{2} -2)$

Solving and simplifying it further we get:

Using distributive property, we get

$-6x^{2} (4x)-6x^{2} (-7x^{2} )-6x^{2} (-2x)$

= $-24x^{3}+42x^{4}+12x^{2}$

Now re- arranging the equation we get,

$42x^{4} -24x^{3} +12x^{2}$

Therefore, option D is correct.

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Please help fassssst

Zarrin [17]

Answer:

$\dfrac{9}{2}$

Step-by-step explanation:

You can do this using the quadratic equation:

$x =\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

Let's first setup our expression:

4x² + 12x = 135

the quadratic formula is:

ax² + bx + c = 0

4x² + 12x - 135 = 0

Then:

a = 4

b = 12

c = -135

Now we plug in our coefficients and solve:

$x =\dfrac{-12\pm\sqrt{12^{2}-4(4)(-135)}}{2(4)}$

We solve for both to determine the positive one:

$x =\dfrac{-12+ \sqrt{12^{2}-4(4)(-135)}}{2(4)}$ $x =\dfrac{-12- \sqrt{12^{2}-4(4)(-135)}}{2(4)}$

$x =\dfrac{-12+ \sqrt{144+2160}}{8}$ $x =\dfrac{-12- \sqrt{144+2160}}{8}$

$x =\dfrac{-12+ \sqrt{2304}}{8}$ $x =\dfrac{-12- \sqrt{2304}}{8}$

$x =\dfrac{-12+ 48}{8}$ $x =\dfrac{-12- 48}{8}$

$x =\dfrac{36}{8} = \dfrac{9}{2}$ $x =\dfrac{-60}{8} = \dfrac{-15}{2}$

So if you are looking for a positive solution, just take the positive one as x.

8 0

3 years ago

The number of electrical outages in a city varies from day to day. Assume that the number of electrical outages ( x ) in the cit

svlad2 [7]

Answer:

0.26 and 0.577

Step-by-step explanation:

Given :

x :___0 ___ 1 ____ 2 ____ 3

f(x):_0.80 _0.15__0.04 __0.01

The mean :

E(X) = Σ(x * p(x))

E(X) = (0*0.8) + (1*0.15) + (2*0.04) + (3*0.01)

E(X) = 0 + 0.15 + 0.08 + 0.03

E(X) = 0.26

Var(X) = Σx²*p(x)) - E(x)²

Σx²*p(x)) = (0^2*0.8) + (1^2*0.15) + (2^2*0.04) + (3^2*0.01) = 0.4

Σx²*p(x)) - E(x)² = 0.4 - 0.26² = 0.3324

Std(X) = √0.334 = 0.577

7 0

3 years ago

Give an explaination on what Comparing integers is

Paraphin [41]

Okay so basically an integer is just a whole number that isn’t a fraction. Comparing integers is basically comparing whole numbers. For example, comparing the numbers 2 and 34 would be 2<34 and that’s comparing them to each other! :)

3 0

3 years ago

What is 674×673×142÷3

anzhelika [568]

Step-by-step explanation:

$674 \times 673 \times 142 \div 3 \\ \\ = 674 \times 673 \times 142 \times \frac{1}{3} \\ \\ = 64,411,484\times \frac{1}{3} \\ \\ = 21,470,494.7 \\$

8 0

3 years ago

In her metalwork class, Anja cut a square of

Paul [167]

Given:

Anju cut square of tin, of edge 3.7 cm, from a larger square of edge 6.3 cm.

To find:

The area of the remaining tin.

Solution:

Area of a square is:

$Area=a^2$

Where, a is the edge of the square.

Area of the smaller square is:

$A_1=(3.7)^2$

$A_1=13.69$

Area of the larger square is:

$A_2=(6.3)^2$

$A_2=39.69$

The area of the remaining tin is:

$A=A_2-A_1$

$A=39.69-13.69$

$A=26$

Therefore, the area of the remaining tin is 26 sq. cm.

8 0

2 years ago