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kirill115 [55]
2 years ago
13

What is this, (2r-1)(r-1)? I'm so confused.

Mathematics
2 answers:
kondaur [170]2 years ago
5 0
(2r-1)(r-1)
=2r(r-1) -1(r-1)
= 2r^2-2r-r+1
=2r^2-3r+1
11Alexandr11 [23.1K]2 years ago
4 0

Answer:

It looks like the factored form of a polynomial

Step-by-step explanation:

In unfactored form, it would be this:

2r^2 + -2r + 1

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Above, I changed the fraction form of x and y into exponential form so it is easier to see the differentiation. Now, we can differentiate:

-1x^{-2}+-1y^{-2}\frac{dy}{dx}=5\\\\\frac{-1}{x^2}-\frac{1}{y^2}\frac{dy}{dx}=5\\\\-\frac{1}{y^2}\frac{dy}{dx}=5+\frac{1}{x^2}\\\\\frac{dy}{dx}=-5y^2-\frac{y^2}{x^2}

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Step-by-step explanation:

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