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kirill115 [55]
3 years ago
13

What is this, (2r-1)(r-1)? I'm so confused.

Mathematics
2 answers:
kondaur [170]3 years ago
5 0
(2r-1)(r-1)
=2r(r-1) -1(r-1)
= 2r^2-2r-r+1
=2r^2-3r+1
11Alexandr11 [23.1K]3 years ago
4 0

Answer:

It looks like the factored form of a polynomial

Step-by-step explanation:

In unfactored form, it would be this:

2r^2 + -2r + 1

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Answer:

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Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the average using the finite correction factor is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}

The information provided is:

N=1500\\n=183\\\sigma=1.47\\\bar x=3.3

The critical value of <em>z</em> for 95% confidence level is,

<em>z</em> = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}

     =3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

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