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3 years ago

Please help me I need to submit this asap

Mathematics

1 answer:

frez [133]3 years ago

8 0

Answer:

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here { a, b ] = [ - 1, 2 ], thus

f(b) = 4 ← from (2, 4 )

f(a) = $\frac{1}{2}$ ← from (- 1, $\frac{1}{2}$ ) , thus

average rate of change = $\frac{4-\frac{1}{2} }{2-(-1)}$ = $\frac{\frac{7}{2} }{3}$ = $\frac{7}{6}$ → D

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Factor 36a^2x - b^2

rodikova [14]

Answer:

36a2 - b2

Step-by-step explanation:

( 6a + b)( 6a - b)

36a2 - b2

6^2 a2 - b^2

x2 y2 = (xy)2

(6a)2 - b^2

(6a + b)(6a - b)

Hope that helps :)

8 0

3 years ago

6 plates and 5 cups cost 32.10 dollars. 7 plates and 6 cups cost 37.70 dollars. Each plate costs the same amount as the other pl

slavikrds [6]

Answer:

Plates are 2.80 Dollars and cups are 1.40 dollars

Step-by-step explanation:

Cups = c

Plates = p

6p + 5c = 23.80 ==> multiply by 6 ==> 36p + 30c = 142.80

7p + 6c = 28.00 ==> multiply by 5 ==> 35p + 30c = 140.00

Now use algebra to have the 30c be on one side and the rest on the other:

36p + 30c = 142.80 | -36p

30c = 142.80 - 36p

35p + 30c = 140.00 | -35p

30c = 140.00 - 35p

Now set them equal to each other about the 30c:

142.80 - 36p = 140.00 - 35p

Use algebra to solve for p:

142.80 - 36p = 140.00 - 35p | +36p

142.80 = 140.00 + p | - 140

2.80 = p

Go back to one of the "30c" equations and plug in the value for p:

30c = 140 - 35p

30c = 140 - 35(2.80)

30c = 140 - 98

30c = 42 | /30

c = 42/30

c = 1.4

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=f%20-%20354%20%3D%201221" id="TexFormula1" title="f - 354 = 1221" alt="f - 354 = 1221" align="

alukav5142 [94]

$f-354=1221$ <em>add 354 to both sides</em>

$f+354-354=1221+354\\\\\boxed{f=1,575}\to\boxed{D.}$

6 0

3 years ago

A track team will run a 4 mile relay race. The coach divided the students into groups of 4. The first runner of each group would

natita [175]

If a track team is running a relay race, shouldnt they be running the same distance? The fourth person who runs is going to be running alot more than everyone else.

3 0

3 years ago

I need to find the greatest common factor of <img src="https://tex.z-dn.net/?f=40s%5E3t%5E5" id="TexFormula1" title="40s^3t^5" a

solong [7]

Answer:

$\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}$

Step-by-step explanation:

$40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4$

7 0

4 years ago