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tresset_1 [31]
3 years ago
11

Simplify i^82 pls...thanks :)

Mathematics
2 answers:
Fofino [41]3 years ago
8 0
To simplify i^82, divide 82 by. the answer is 20 with remainder 2
Kruka [31]3 years ago
8 0

Answer:

-1

Step-by-step explanation:

I simplified the expression using the definition of an imaginary number i=√1

First I applied the exponent rule: a^{bc}=\left(a^b\right)^c

i^{82} = \left(i^2\right)^{41}

=\left(i^2\right)^{41}

Then, I applied the maginary number rule: \:i^2=-1

=\left(-1\right)^{41}

Then I used the exponent rule again: \left(-a\right)^n=-a^n,\:\mathrm{if\:}n\mathrm{\:is\:odd}

\left(-1\right)^{41}=-1^{41}

=-1^{41}

Sooo, 1^{41}=1, which equals =-1.

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3. Using the sample size of 800 and the proportion 0.47, calculate the margin of error associated with the estimate of the propo
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Answer:

ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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Solution to the problem

We assume for this case a confidence level of 95%. In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

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The margin of error for the proportion interval is given by this formula:  

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And if we replace the values obtained we got this:

ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346  

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