Answer:
No
Step-by-step explanation:
Does anyone have to do DELTA-MATH
Answer:
\[y < = 300\]
Step-by-step explanation:
Let x = number of out-of-state students at the college
Let y = number of in-state students at the college
As per the given problem, the constraints are as follows:
\[x < = 100\] --------- (1)
\[y = 3 * x\] --------- (2)
From the given equations (2), \[ x = y/3 \]
Substituting in (1):
\[y/3 < = 100\]
Or, \[y < = 300\] which is the constraint representing the incoming students.
To solve for this, set up a proportion.
21/40 = x/100.
Cross multiply the fraction's numerators with the denominators;
21 x 100, 40 and x.
2100/40x.
Divide both numbers by 40 to get x.
2100/40 = 52.5
21 is 52.5% of 40.
I hope this helps!
C=2
r
A=
r<span>²
C=2</span>
r=58
2r=58
r=29
A=
r<span>²
A=29</span><span>²</span>
A=841
I think you just have to add all of the totals up??
