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ValentinkaMS [17]
2 years ago
15

Find the slope of each line.

Mathematics
1 answer:
REY [17]2 years ago
4 0
The slope is 4/3.
I hope this helps :)
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A researcher asks students to rate their feeling toward an increase in tuition on a seven-point scale ranging from "opposed" to
ElenaW [278]

Answer: B

Step-by-step explanation:

In statistical terms ,ordinal scale contains things that you can place in order.

For example, hottest to coldest, lightest to heaviest, richest to poorest. Basically, if you can rank data by 1st, 2nd, 3rd place (and so on), then you have data that’s on an ordinal scale.

7 0
2 years ago
Which is another way to write 42+63?
eduard
Forty two plus sixty three that's your answer 
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3 years ago
A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per
Tems11 [23]

Answer:

The pressure is changing at \frac{dP}{dt}=3.68

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of \frac{dV}{dt}=-4 \:{\frac{cm^3}{min}} and we want to find at what rate is the pressure changing.

The equation that model this situation is

PV^{1.4}=k

Differentiate both sides with respect to time t.

\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)

Apply this rule to our expression we get

V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0

Solve for \frac{dP}{dt}

V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}

when P = 23 kg/cm2, V = 35 cm3, and \frac{dV}{dt}=-4 \:{\frac{cm^3}{min}} this becomes

\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68

The pressure is changing at \frac{dP}{dt}=3.68.

7 0
3 years ago
You have just hired a new employee, Tim, to oversee the production of your new line of water bottles. Tim is a full-time employe
Whitepunk [10]

Answer:

  $16,640

Step-by-step explanation:

Tim's total annual wage expense is ...

  ($8.00 /h)(40 h/wk)(52 wk/yr) = $8×40×52 /yr = $16,640 per year

3 0
3 years ago
How to graph f(x)=(x-2)^2+3
iris [78.8K]

Using translation concepts, the graph of f(x) = (x - 2)² + 3 is given at the end of the question.

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

In this problem, we have that the parent and the translated function are given, respectively, by:

  • g(x) = x².
  • f(x) = (x - 2)² + 3.

The translations are as follows:

  • Right two units, as x -> x - 2.
  • Up 3 units, because f(x) = g(x) + 3.

Hence the graphs are given at the end of the answer, with the parent function in red and the translated function f(x) = (x - 2)² + 3 in green.

More can be learned about translation concepts at brainly.com/question/4521517

#SPJ1

5 0
2 years ago
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