It is given that AB is parellel to CD. These two lines are cut by a transversal, creating angles BAC and DCA. Thus, angle BAC is congruent to angle DCA because alternate interior angles are congruent. It is also given that angle ACB is congruent to angle CAD. Therefore, triangle ABC is congruent to triangle CDA because of the ASA theorem.
Answer:
Step-by-step explanation:
Which of the following graphs best represents the solution to the pair of equations below? y = −x + 6 y = 2x − 3 A coordinate plane is shown with two lines graphed. One line passes through the y axis at 6 and through the x axis at 6. The other line passes through the y axis at negative 3 and the x axis at 1.5. The lines intersect at the point 3 comma 3. A coordinate plane is shown with two lines graphed. One line passes through the y axis at 6 and the x axis at 6. The other line passes through the y axis at 3 and the x axis at negative 1.5. The lines intersect at 1 comma 5. A coordinate plane is shown with two lines graphed. One line passes through the y axis at 6 and the x axis at negative 6. The other line passes through the y axis at negative 3 and the x axis at negative 1.5. The lines intersect at negative 3 and 3. A coordinate plane is shown with two lines graphed. One line passes through the y axis at 6 and the x axis at negative 6. The other line passes through the y axis at 3 and the x axis at 1.5. The lines intersect at negative 1 comma 5.
Answer:
-128x + 48 = -15
Step-by-step explanation:
I don't any choices to pick from but using the distributive property you will multiply the -4 by everything in the parenthesis.
-4(32x - 12) = -15
=-128x + 48 = -15.
It would be log3 14/log3 4
Hope this helps. (:
