Given
Expenditures at Manager's Store; expenditures at Competitor's Store.
Find
a) average spent at each store
b) which store is better represented by the mean value
c) an explanation for the answer in ≥ 2 sentences
Solution
a) The sum of expenditures divided by the number of expenditures (15) is ...
... average for Manager's Store: $37.60
... average for Competitor's Store: $48.53
b) The expenditures at Manager's Store are well-represented by the mean (average).
c) The range of expenditures at Competitor's Store is significantly higher than at Manager's store, so a single number such as mean or median does not represent the data well. The expenditures at Manager's store are more compactly grouped around the mean and median, which are closer together, so the mean is a good representation of Manager's Store expenditures overall.
Answer:
1/3
Step-by-step explanation:
-6+(-1/3)= -19/3
-19/3 + 20/3 = 1/3
This an { } solution because the absolute value is always a positive number unless there is a negative sign in front of the brackets.
hope this helps :)
V = 1/3* h * r^3 pi
V ' = 1/3* h/3* (2r)^3 pi = h/9 * 8r^3 * pi
V ' / V = (h/9 * 8r^3 * pi) ÷ ( 1/3* h * r^3 pi ) = (8 * 3)/ 9 = 8 /3
(x,y)=(2,3)
This is Answer
