The "x-intercept" occurs when y=0, because it is at this point that the equation touches the x axis. So if you plug in y=0 into the equation you can solve for the x coordinate.
4x-2(0)-8=0
4x-8=0
4x=8
x=2
So the x-intercept is the point (2,0)
Answer:
360
Step-by-step explanation:
15+15
12x15
The distance d is 9 ft and the height is 12ft.
<h3>
How to find the distance and the height?</h3>
Here we can model the situation with a right triangle, where the length of the wire is the hypotenuse.
The height is one cathetus and the distance is the other catheti.
Let's define:
- h = height
- d = distance.
- hypotenuse = 15ft
We know that the height of the tower is 3 ft larger than the distance, then:
h = d + 3ft
Now we can use the Pythagorean theorem, it says that the sum of the squares of the cathetus is equal to the square of the hypotenuse.
Then:
![d^2 + (d + 3ft)^2 = (15ft)^2](https://tex.z-dn.net/?f=d%5E2%20%2B%20%28d%20%2B%203ft%29%5E2%20%3D%20%2815ft%29%5E2)
Now we can solve this equation for d:
![d^2 + d^2 + 6ft*d + 9ft^2 = (15ft)^2\\\\2d^2 + 6ft*d - 216 ft^2 = 0\\\\d^2 + 3ft*d - 108ft^2 = 0](https://tex.z-dn.net/?f=d%5E2%20%2B%20d%5E2%20%2B%206ft%2Ad%20%2B%209ft%5E2%20%3D%20%2815ft%29%5E2%5C%5C%5C%5C2d%5E2%20%2B%206ft%2Ad%20-%20216%20ft%5E2%20%3D%200%5C%5C%5C%5Cd%5E2%20%2B%203ft%2Ad%20-%20108ft%5E2%20%3D%200)
Then the solutions are:
![d = \frac{-3ft \pm \sqrt{(3ft)^2 - 4*(-108ft^2)} }{2} \\\\d = \frac{-3ft \pm 21ft }{2}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B-3ft%20%5Cpm%20%5Csqrt%7B%283ft%29%5E2%20-%204%2A%28-108ft%5E2%29%7D%20%7D%7B2%7D%20%5C%5C%5C%5Cd%20%3D%20%5Cfrac%7B-3ft%20%5Cpm%2021ft%20%7D%7B2%7D)
We only take the positive solution:
d = (-3ft + 21ft)/2 = 9ft
And the height is 3 ft more than that, so:
h = 9ft + 3ft = 12ft
The distance d is 9 ft and the height is 12ft.
If you want to learn more about right triangles:
brainly.com/question/2217700
#SPJ1
Answer:
£342,000
Step-by-step explanation:
190,000 x 1.8=342,000
for 1 year