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3 years ago

Help me answer this plz I really need help

Mathematics

2 answers:

maw [93]3 years ago

5 0

Answer:

E (b/3) +3

Step-by-step explanation:

3c =b

c+3 = ?

Solve the first equation for c

3c=b

Divide by 3

3c/3 = b/3

c = b/3

Now replace c with b/3 in c+3

c+3

(b/3) +3

expeople1 [14]3 years ago

4 0

Answer:

Answer E. is correct

Step-by-step explanation:

b = 3 * c --> c = 1/3 * b

c + 3 = 1/3 * b + 3 --> E.

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Dmitry_Shevchenko [17]

Answer:

<h2>Option B </h2>

Step-by-step explanation:

As,

It has shown that line c cuts line b by making 90° so those lines are called perpendicular bisectors .

Hence,

Option B is the correct symbol shown for perpendicular bisector of line c to line b.

8 0

3 years ago

Solve equation 3x-5y=7 5x-2y=-1 by elimination

kakasveta [241]

Answer:

x = -1, y = -2.

Step-by-step explanation:

Using the elimination method,

multiply the first eqn by 2 and the 2nd eqn by 5.

6x - 10y = 14

25x - 10y = -5

Subtract one of the new equations from the other

-19x = 19

x = -1

Sub x=-1 into the 2nd eqn

-5 - 2y = -1

y = -2

Hence x = -1, y = -2.

7 0

3 years ago

Read 2 more answers

Inverse of y=(x/2)^2

Lady bird [3.3K]

Tell me if the answer is true or wrong

6 0

3 years ago

Simplify the expresion <img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B3.%20%5Csqrt%5B4%5D%7B432%7D%20%7D%20" id="TexF

Bond [772]

$\sqrt[4]{3. \sqrt[4]{432}}$
= $\sqrt[4]{3. \sqrt[4]{2^4.3^3} }$
= $\sqrt[4]{3.2.3^\frac{3}{4}}$
= $3^\frac{1}{4}.2^\frac{1}{4}.3^\frac{3}{16}$
= $3^\frac{7}{16}.2^\frac{1}{4}$

6 0

3 years ago

Please help asap!!!!!!

Julli [10]

Answer:

35°

Step-by-step explanation:

3 0

3 years ago