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3 years ago

14

Of the 48 dogs enrolled in obedience

1 answer:

Serga [27]3 years ago

8 0

36/48=6/8=3/4 so 75% completed training

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For each right triangle below, find the missing side (Pythagorean’s Theorem) and the missing angle (Angle Sum theorem.)

valkas [14]

Answer:

a=21.2

n=√29

Step-by-step explanation:

$90+68.2+a=180$

$a+158.2=180$

$a=21.2$

$2^2+5^2=n^2$

$4+25=n^2$

$n^2=29$

$n=\sqrt{29}$

3 0

2 years ago

Determine the point on the graph of the linear equation 2x + 5y = 19, whose ordinate is 1 1/2 times its abscissa.

rosijanka [135]

Answer:

(2, 3)

Step-by-step explanation:

2x + 5y = 19

5y = -2x + 19

y = $-\frac{2}{5} x + \frac{19}{5}$

P(abscissa, ordinate)

P(x, 1.5x)

P(2, 3)

$3 = -\frac{2}{5} (2) + \frac{19}{5}$

$3 = -\frac{4}{5} + \frac{19}{5}$

3 = 15/5

3 = 3

8 0

3 years ago

HELP ASAPPPP PLEASE I NEED TO FINISH ASAP

defon

Answer:

-15.3, -15.1, -12.3, -11.4, -11.4, 19.6

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

I the radius of a circle is x cm ,what is the length of circufernece?

nordsb [41]

Answer:

44x/7

Step-by-step explanation:

Radius=r=xcm

Circumference=2πr

➜2πx

➜2×22/7×x

➜44/7×x

➜44x/7

4 0

3 years ago

4/x-1+6/x+1=-12/x^2-1

Mademuasel [1]

$\frac{4}{x - 1} + \frac{6}{x + 1} = \frac{-12}{x^{2} - 1}$

$\frac{4(x + 1)}{(x - 1)(x + 1)} + \frac{6(x - 1)}{(x - 1)(x + 1)} = \frac{-12}{x^{2} - 1}$

$\frac{4x + 4}{x^{2} - 1} + \frac{6x - 6}{x^{2} - 1} = \frac{-12}{x^{2} - 1}$

$\frac{10x - 2}{x^{2} - 1} = \frac{-12}{x^{2} - 1}$

$(10x - 2)(x^{2} - 1) = -12(x^{2} - 1)$
$10x^{3} - 10x^{2} - 2x^{2} + 2 = -12(x^{2}) + 12(1)$
$10x^{3} - 12x^{2} + 2 = -12x^{2} + 12$
$10x^{3} - 12x^{2} + 12x^{2} + 2 = -12x^{2} + 12x^{2} + 12$
$10x^{3} + 2 - 2 = 12 - 2$
$\frac{10x^{3}}{10} = \frac{10}{10}$

$x^{3} = 1$
$x = 1$

4 0

3 years ago