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gavmur [86]
3 years ago
9

Please help me solve this problem

Mathematics
2 answers:
jeka943 years ago
8 0
Multiply both sides by lh, V=wlh
Rudik [331]3 years ago
7 0

Answer:

V = wlh

Step-by-step explanation:

Given

w = \frac{V}{lh} ( multiply both sides by lh to clear the fraction )

wlh = V

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The correct answer is c y-5=4(x-7)
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Find the midpoint from (-2,-2) to (6,6)
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(2,2)


(x1+x2)/2, (y1-y2)/2
(-2+6)/2=(2)
(-2+6)/2=2
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1.1
solniwko [45]

Answer:

Cost = 112.266 cent/km

Step-by-step explanation:

Given

Unit\ cost = R17.82/litre

Rate = 6.3litre/100km

Required

The fuel cost in cent\ per\ km

This is calculated using:

Cost = Unit\ cost * Rate

Cost = R17.82/litre * 6.3litre/100km

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6 0
3 years ago
4. Diego is thinking of two positive numbers. He says, "If we triple the first number and
aleksandr82 [10.1K]

Answer:

3<em>x </em>+ 2<em>y</em> = 34. and two possible pairs of positive numbers are  (<em>x</em>, <em>y</em>) = (10, 2) and (<em>x</em>, <em>y</em>) = (4, 11).

Step-by-step explanation:

 Let the First positive number be <em>x</em> and second positive number be <em>y.</em>

Triple of first number = 3<em>x</em>

double of second number = 2<em>y</em>

According to question,

3<em>x </em>+ 2<em>y</em> = 34

Therefore, the equation is 3<em>x </em>+ 2<em>y</em> = 34

So the two possible pair of numbers Diego would be thinking of must satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34

Now,  3<em>x </em>+ 2<em>y</em> = 34

3<em>x </em>= 34 - 2<em>y</em>

Let x = 10 and by substituting its value in above expression,

3 \times 10 = 34 - 2y

30 = 34 - 2y

2y = 34 - 30

2y = 4

y = 2

Therefore first pair (<em>x</em>, <em>y</em>) = (10, 2)

In the same way put x = 4 then,

3<em>x </em>= 34 - 2<em>y</em>

3 \times 4 = 34 - 2y

2y = 34 - 12

2y = 22

y = 11

Therefore first pair (<em>x</em>, <em>y</em>) = (4, 11)

Therefore, (<em>x</em>, <em>y</em>) = (4, 11) and  (<em>x</em>, <em>y</em>) = (10, 2) are the two possible pairs of numbers Diego could be thinking of as these both values satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34.  

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