m = (y2-y1)/(x2-x1)
m = (6-4)/(4-0)
m = 2/4
y = mx + c
6 = (2/4)(4) + c
c = 4
Thus, the equation is y = (2/4)x +4
The answer to this question is D.
Let the length of the north and south sides be x, then the length of the east and west side is 32/x.
The total fencing needed is the perimeter of the rectangle = 2x + 2(32/x) = 2x + 64/x
Cost of fencing the north and south sides is 2(2x) = 4x
Cost of fencing the east and west sides is 4(64/x) = 256/x
Total cost (C(x)) of fencing the vegetable patch is 4x + 256/x
For minimum cost dC/dx = 0
4 - 256/x^2 = 0
4x^2 - 256 = 0
x^2 = 64
x = 8
Therefore, the <span>dimensions of the vegetable patch with the least expensive fence is
</span><span>north and south sides = 8 ft
</span><span>east and west sides = 32/8 = 4 ft</span>
Answer:
the answer is 5b^3+8
Step-by-step explanation:
The answer is 10. Why? Well, see below for a list of steps and an explanation!
The answer to this problem is 10 because by using order of operations/PEMDAS, we can start the evaluation by solving P, which stands for Parenthesis.
Since 8 + 20 is inside parenthesis, we can start by solving this portion.
8 + 20 = 28
Now, for the next step, we can simplify by plugging 28 into the expression.
28 / 4 + 3
The E in PEMDAS stands for Exponents, but we can skip this step since there are none.
The M in PEMDAS stands for Multiplication, but we can skip this step since there is nothing to multiply.
The D in PEMDAS stands for Division, and there does happen to be division in this expression!
28 / 4 = 7
Now that we have our division portion solved, we can simplify the problem again by plugging 7 into the expression.
7 + 3
Now that we have our final simplification, we can add to get our answer.
7 + 3 = 10
Therefore, your answer is 10.
Your final answer: 10 is your final answer. If you need help, let me know and I will gladly assist you.
