Answer:
<u>The box with largest volume is Box A. Its volume of 67,375 cm³ (cubic centimeter) or 0.068 m³(cubic meter) is higher than box B and box C.</u>
Step-by-step explanation:
1. Given that we know the three dimensions (length, width and height) of each box, we will use the following formula for calculating the volume:
Volume = Length * Width * Height
Box A
Volume = Length * Width * Height
Volume = 35 * 35 * 55
Volume = 67,375 cm³
Converting to m³ = 67,375 * 10⁻⁶ = 0.068 m³ (Rounding to 3 decimal places)
Box B
Volume = Length * Width * Height
Volume = 40 * 40 * 40
Volume = 64,000 cm³
Converting to m³ = 64,000 * 10⁻⁶ = 0.064 m³ (Rounding to 3 decimal places)
Box C
Volume = Length * Width * Height
Volume = 60 * 30 * 30
Volume = 54,000 cm³
Converting to m³ = 54,000 * 10⁻⁶ = 0.054 m³ (Rounding to 3 decimal places)
<u>The box with largest volume is Box A. Its volume of 67,375 cm³ (cubic centimeter) or 0.068 m³(cubic meter) is higher than box B and box C.</u>
Answer:
Given
Edge of a cube = 10cm
Length, l = 12.5 cm
Breadth, b = 10cm
Height, h = 8 cm
Find out
We have to find
i) Which box has the greater lateral surface area and by how much?
ii) Which box has the smaller total surface area and by how much?
Solution
(i)
Lateral surface area of a cube = 4 * (edge)2
= 4 * 102 cm2
= 400 cm2
Lateral surface area of a cuboid = 2 (lh + bh)
= 2 (12.5 * 8 + 10 * 8) cm2
= 2 (100 + 80) cm2
= 360 cm2
So, the lateral surface area of the cubical box is greater than cuboidal box by (400 cm2 – 360 cm2) which is 40 cm2.
(ii)
Total surface area of a cube = 6 * (edge)2
= 6 * 102 cm2
= 600 cm2
Total surface area of cuboid = 2 (lb + bh + lh)
= 2 (12.5 * 10 + 10 * 8 + 12.5 * 8) cm2
= 2 (125 + 80 + 100) cm2
= 610 cm2
Therefore, the total surface area of the cuboidal box is greater than the cubical box by (610 cm2 – 600 cm2) which is 10 cm2.
60/8 = 7.5
Thus, she will need 8 containers to put 60 beads.
Answer:
36
Step-by-step explanation:
36-25=11
36+11=47
Well, it depends on the school. Do you have a list of the classes?
