Question

If a 0.10−mL volume of oil can spread over a surface of water of about 47.0 m2 in area, calculate the thickness of the layer in centimeters. Enter your answer in scientific notation.

Answer 1

Answer:

$2.1276595745\times 10^{-7}\ cm$

Explanation:

Volume of oil = 0.1 mL = 0.1 cm³

Area of oil = $47\ m^2$

Converting to $cm^2$

$1\ m=10^2\ cm$

$1\ m^2=10^4\ cm^2$

$47\ m^2=47\times 10^4\ cm^2$

Volume is given by

$V=At\\\Rightarrow t=\dfrac{V}{A}\\\Rightarrow t=\dfrac{0.1}{47\times 10^4}\\\Rightarrow t=2.1276595745\times 10^{-7}\ cm$

The thickness of the layer is $2.1276595745\times 10^{-7}\ cm$