Question

There are two space ships traveling next to each other. The first one is 500

Answer 1

This question involves the concept of  Newton's law of gravitation.

The force of gravity between the two spaceships is "1355.78 N".

Newton's Law Of Gravitation

According to Newton's Law of Gravitation:

$F=\frac{Gm_1m_2}{r^2}$

where,

• F = force of gravity between ships = ?
• G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
• m₁ = mass of first ship = 500 kg
• m₂ = mass of second ship = 498 kg
• r = distance between ships = 35 m

Therefore,

$F=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(500\ kg)(498\ kg)}{(35\ m)^2}$

F = 1355.78 N = 1.356 KN

Learn more about Newton's Law of Gravitation here:

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Answer 2

Two space ships traveling next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.

It is given that the First spaceship's weight ($m_{1}$) is 500 kg,

The second spaceship's weight ($\rm m_{2}$) is 498 kg.

The distance between spaceships (r) is 35 meters.

It is required to find the Force of gravity between these spaceships.

What is Gravitational force?

It is defined as the force which attracts any two masses in the universe.

By Newton's law of Gravitation:

$\rm F= \frac{Gm_1m_2}{r^2}$  , Where

$\rm F = The\ force \ of \ gravity \ between \ the \ spaceships\\\rm G= Universal\ Gravitational \ Constant = 6.67 \times 10^{-11} N.m^2/kg^2$

Putting values in the above formula:

$\rm F = \frac{(6.67\times 10^{-11} N.m^2/kg^2)(500kg)(498kg)}{(35m)^2}$

F = 1355.78 N = 1.356  KN

Thus, Two spaceships travel next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.

Learn more about Gravitational Force here:

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