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Lynna [10]
3 years ago
12

A 10.5- resistor, a 15.9-μF capacitor, and a 15.2-mH inductor are connected in series with a 203-V generator. (a) At what frequ

ency is the current a maximum? (b) What is the maximum value of the rms current? Note: The ac current and voltage are rms values and power is an average value unless indicated otherwise.
Physics
1 answer:
yKpoI14uk [10]3 years ago
7 0

Answer:

(a) Frequency at which current is maximum is 323.9 Hz

(B) Maximum current in the circuit is 19.333 A

Explanation:

We have given resistance R = 10.5 ohm

Capacitance C=15.9\mu F=15.9\times 10^{-6}F

Inductance L=15.2mH=15.2\times 10^{-3}H

(a) Current is maximum when impedance will be minimum and impedance is minimum when there is condition of resonance.

At resonance X_C=X_L

\frac{1}{\omega C}=\omega L

\omega ^2=\frac{1}{15.9\times 10^{-6}\times 15.2\times 10^{-3}}

\omega =2034.13

2\pi f =2034.13

f = 323.9 Hz

(b) Current will maximum when resonance occurs at resonance impedance of the circuit is equal to resistance.

Voltage is given V = 203 volt

So maximum current i=\frac{203}{10.5}=19.333A

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