Answer:
C
Explanation:
<link rel="stylesheet" type="text/css" href="syb/syb.css" title="stylesheet"/>
The above code is self explanatory. All others have wrong rel or title. Title is always stylesheet, and rel as well stylesheet as well as href is external css file which we are loading, and text/css is always the type as it is the css. None of the other has this syntax. And hence this is the right answer.
Modern computers use in side a memory board to store info but back then you would use flappy disks
Answer:
The program in Python is as follows:
word = input("Word: ")
if len(word) < 5:
print("At least 5 characters")
else:
pal = word[0:5]
word = word[0:4]
word = word[::-1]
pal+=word
print(pal)
Explanation:
This gets the word from the user
word = input("Word: ")
This checks if the length of the word is less than 5.
if len(word) < 5:
If yes, this tells the user that at least 5 characters is needed
print("At least 5 characters")
If otherwise
else:
This extracts the first 5 characters of the word into variable named pal
pal = word[0:5]
This extracts the first 5 characters of the word into variable named word
word = word[0:4]
This reverses variable word
word = word[::-1]
This concatenates pal and word
pal+=word
This prints the generated palindrome
print(pal)
Answer:
- Code is in JAVA language. As there is no user input the logic is straightforward.
- Below is the code along with a detailed explanation of the logic.
- The class name is Print main save as file as the main class.
Explanation:
Program:-
public class Main{
public static void main(String args[]){
/* There are two for loops...
* First for loop runs from i=1 to i=9
* Second for loop runs from j=1 to j=i.
*
*/
for(int i=1;i<=9;i++){
for(int j=1;j<=i;j++){ // j loop runs from j=1 to j=i
/*Prints I and j next to each other*/
System.out.println(i+""+j);
}//for loop of j ends here
}// for loop of I ends here
}
}
Answer:
negatives = []
zeros = []
positives = []
while True:
number = input("Enter a number: ")
if number == "":
break
else:
number = int(number)
if number < 0:
negatives.append(number)
elif number == 0:
zeros.append(number)
else:
positives.append(number)
for n in negatives:
print(n)
for z in zeros:
print(z)
for p in positives:
print(p)
Explanation:
Initialize three lists to hold the numbers
Create a while loop that iterates until the user enters a blank line
Inside the loop:
If the number is smaller than 0, put it in the negatives list
If the number is 0, put it in the zeros list
Otherwise, put the number in the negatives list
When the while loop is done, create three for loops to print the numbers inside the lists
