Answer:
A) P(10 on three rolls) = 1/1728 = 0.0005787
B) P(10 in two of three rolls) = 11/1728 = 0.0063657
Step-by-step explanation:
Each die has 6 possible values, so a pair of dice have a total of 6*6=36 outcomes.
To find a sum of 10, the cases are:
(4,6), (5,5) and (6,4).
So to have a sum of 10 we have 3 cases among the 36 possible, therefore the probability is:
P(10) = 3/36 = 1/12
A)
If we want the sum of 10 in each of the three rolls, the probability is:
P(10 on three rolls) = P(10)^3 = (1/12)^3 = 1/1728 = 0.0005787
B)
If the sum is 10 in two of three rolls, in one roll we need the probability of the sum not being 10:
P(not 10) = 1 - P(10) = 1 - (1/12) = 11/12
So we have:
P(10 in two of three rolls) = P(10)^2 * P(not 10) = (1/12)^2 * (11/12)
P(10 in two of three rolls) = 11/1728 = 0.0063657
