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Elanso [62]
4 years ago
15

Analyze the diagram below and complete the instructions that follow. Solve for x.

Mathematics
1 answer:
Oxana [17]4 years ago
4 0
To solve for x you'll add 6x and 4x and set them equal to 90 since they are complementary. 

6x+4x = 90
10x = 90 
x = 9

Hope this helps :)
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Multiply or divide as indicated. r 2 • r • r 5
Zielflug [23.3K]
When multiplying variables , the rule is: if the bases are the same,
Keep the base and ADD the powers.
r^2 * r^1 * r^5
Notice that the r with no power written is an assumed power of 1.
r^8 is the answer
4 0
4 years ago
Read 2 more answers
If line t is a transversal of lines l and m, name the angle relationship of the given angle pairs.
Ghella [55]

Answer:

\angle 1\ and\ \angle 3 are corresponding angles and are congruent to each other.

\angle 8\ and\ \angle 4 are alternate exterior angles and thus congruent to each other.

\angle 2\ and\ \angle 3 are interior angles on the same side, and they are supplementary(sum=180°).

Step-by-step explanation:

Given:

Line l\parallel m

Line t is traversal.

By angle properties we can name the angle relationship of given angle pairs.

\angle 1\ and\ \angle 3 are corresponding angles and are congruent to each other.

\angle 8\ and\ \angle 4 are alternate exterior angles and thus congruent to each other.

\angle 2\ and\ \angle 3 are interior angles on the same side, and thus they are supplementary.

8 0
4 years ago
Can anyone help me with my homework
damaskus [11]
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6 0
3 years ago
Two bicycles are traveling along perpendicular roads. Bicycle A is traveling due east at 4 mi/hr, and bicycle B is travelling du
nordsb [41]

Answer:

Step-by-step explanation:

Given

speed of cyclist A is v_a=4 mi/hr

speed of cyclist B is v_b=6 mi/hr

At noon cyclist B is 9 mi away

after noon Cyclist B will travel a distance of 6 t and cyclist A travel 4 t miles in t hr

Now distance of cyclist B from intersection is 9-6t

Distance of cyclist A from intersection is 4 t

let distance between them be z

z^2=(9-6t)^2+(4t)^2

Differentiate z w.r.t time

2z\frac{\mathrm{d} z}{\mathrm{d} t}=2\times (9-6t)\times (-6)+2\times (4t)\times 4

z\frac{\mathrm{d} z}{\mathrm{d} t}=(-6)(9-6t)+4(4t)

\frac{\mathrm{d} z}{\mathrm{d} t}=\frac{16t+36t-54}{z}

Put \frac{\mathrm{d} z}{\mathrm{d} t}\ to\ get\ maximum\ value\ of\ z

therefore 52t-54=0

t=\frac{54}{52}

t=\frac{27}{26} hr

4 0
3 years ago
Reflect (-4,-6) across the y-axis.
Aleksandr-060686 [28]

Answer:

(4,6)

Step-by-step explanation:

since they are negitave number and there being reflected across the y axis they will be positve

6 0
2 years ago
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