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Dimas [21]
3 years ago
14

Can someone please help me with this question? Thanks if you do!

Mathematics
2 answers:
spin [16.1K]3 years ago
7 0

I guess it would be true because 100+95+85+80 = 360, and there are 360 degrees in a circle.


zheka24 [161]3 years ago
5 0

To check if a circle can be circumscribed about a certain quadrilateral, the opposite angles in the quadrilateral have to add up to <u>180</u> degrees.

--------

In your question, the opposite angles in the quadrilateral add up to:

85° + 80° = 165°

and 95° + 100° = 195°

----------------------------------------------------------------

Answer:

As you can see, neither 165° or 195° is 180°.

Therefore the answer is <u>False</u>


------------------------------------------------------------------------------------

<u>Note:</u>

If it's still not to clear for you, then say so and I will provide a diagram to make it clearer,


----------------------------------------------------

<u>Additional Info:</u>

Another word for a quadrilateral that can have a circle circumscribed about it is '<u>Cyclic</u>'.

For example, some shapes are '<u>Cyclic quadrilaterals</u>'

(which means it is a <u>quadrilateral that can fit perfectly into a circle</u>, with all edges touch the circumference)

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3 years ago
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The cost of Samantha's 15th birthday party depends on the number guest. The hall charges $250 for the use of the hall plus $12 p
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3 0
3 years ago
Find the difference: 7 7/8 - 3 1/4
DIA [1.3K]
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8 0
3 years ago
Find the area of the shaded region. Express your answer in terms of pi
Likurg_2 [28]

Area of the shaded region is 540 – 65.25π.    

Solution:

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Width of the rectangle = 18 in

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Radius of the medium circle (r_2) = 9 ÷ 2 = 4.5 in

Radius of the smaller circle (r_3) = 6 ÷ 2 = 3 in

Area of the shaded region = Area of the rectangle – Area of the larger circle – Area of the medium circle – Area of the smaller circle

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                                   =30\times 18-\pi \times 6^2-\pi \times (4.5)^2-\pi \times 3^2

                                   =540-36\pi-20.25\pi-9\pi

                                   =540-65.25\pi

Area of the shaded region is 540 – 65.25π.    

4 0
3 years ago
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