I'm not sure but I would go with c
Answer:
plug in -3 where any x is in the equation. I reccomend doing it in parenthesis just so things work out nicely
Step-by-step explanation:

Given
s=16t^2
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release
Here we're given
s=144 feet
=>
s=144=16t^2
=>
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.
Answer:
y = 2/3x - 3
Step-by-step explanation:
Answer:
1st blank: substitution property of equality
2nd blank: linear pair theorem
3rd blank: substitution property of equality
Step-by-step explanation:
<u>1st blank</u>
∠EIJ ≅ ∠GJI (eq. 1)
∠EIJ ≅ ∠IKL (eq. 2)
∠GJI ≅ ∠JLK (eq. 3)
Substituting eq. 3 into eq. 1:
∠EIJ ≅ ∠JLK
and then, substituting eq. 2:
∠IKL ≅ ∠JLK
which means that m∠IKL = m∠JLK
<u>2nd blank</u>
The Linear Pair Theorem states that two angles that form a linear pair are supplementary
<u>3rd blank</u>
m∠JLK + m∠JLD = 180°
Substituting with the previous result:
m∠IKL + m∠JLD = 180°