Round 8 3/8 to the nearest whole number

If Bill

777dan777 [17]

Answer:

$3,623.84 Exact answer without rounding | $3,623.85 ~ (Approximent Answer with rounding.)

Step-by-step explanation:

Compound Interest Has a Specific Formula:

This case is Exponential Growth.

Formula: y= ab^x

You need to set up the equation.

First we need to define the rate of growth meaning what do you have to do for the 6.5%.

You need to do 100% + 6.5% = 106.5%

You need to convert the percent to a decimal which will be 1.065

Now we need to start plugging things into our formula to solve.

Your initial Starting amount was $3000

So you need to have y=3000(b)^x

We now know that the rate of growth is 1.065 so the b would be 1.065

y=3000(1.065)^x

Our power to x is our 3.5 years.

Our Equation now:

y=3000(1.065)^3

Now you need to use a calculator to do this due to the amount of decimals and digits.

Remember pemdas when doing this!!!

The answer should result to $3,623.84 but if rounded then: $3,623.85

4 0

2 years ago

The inside diameter of a randomly selected piston ring is a random variable with mean value 8 cm and standard deviation 0.03 cm.

S_A_V [24]

Answer:

a) P(7.99 ≤ X ≤ 8.01) = 0.8164

b) P(X ≥ 8.01) = 0.0475.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n can be approximated to a normal distribution with mean

In this problem, we have that:

$\mu = 8, \sigma = 0.03$