We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.
Since these are different, this is not linear.
We now find the second differences:
5-3=2; 7-5=2; 9-7=2. Then:
Since these are the same, this sequence is quadratic.
We use (1/2a)n², where a is the second difference:
(1/2*2)n²=1n².
We now use the term number of each term for n:
4 is the 1st term; 1*1²=1.
7 is the 2nd term; 1*2²=4.
12 is the 3rd term; 1*3²=9.
19 is the 4th term; 1*4²=16.
28 is the 5th term: 1*5²=25.
Now we find the difference between the actual terms of the sequence and the numbers we just found:
4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.
Since this is constant, the sequence is in the form (1/2a)n²+d;
in our case, 1n²+d, and since d=3, 1n²+3.
The correct answer is n²+3
My answer would be to add 3 to both sides
B is 2 and C is 9. AB is 7, AC is 14 and AD is 21. The kine AD has been split into 3 equal sections which are 7 each
Y = 3 will be a straight, horizontal line on 3. It will only touch the y-axis since there's no x. So, the X-Intercept doesn't exist, the Y-Intercept will be (0,3), and the slope of the line is 0.
Answer:
y=1/2x+3.5
Step-by-step explanation:
this one was a bit trickier than the previous one, but i think that that answer is correct. i did the same thing i did to solve your last problem, solved for the slope, and then made a number line and marked the points given, drew a line through the two points, and found where the line intercepted the y axis.
