If an individual has an increased rate of blood flow to the skin,such as would happen with emotion or alcohol consumption ,their skin takes on a reddish tinge.

Explanation:

Our skin is provided with a large number of blood capillaries. These capillaries bring blood and nutrients to the layers of skin. Whenever vasodilation of these capillaries occur, the blood flow to the skin increases and the skin gets a reddish tinge.

During an emotional upsurge such as embarrassment causes the adrenal glands to release adrenaline.

Adrenaline as well as alcohol vasodilates the blood vessels and increases the flow of blood to the skin. Hence, the skin gets a reddish tinge.

3 0

3 years ago

A population of 100 tigers has 30 with horizontal stripes. Using pedigrees, you ascertain that horizontal striping is caused by

bixtya [17]

Assuming that this population is in Hardy-Weinberg equilibrium, we can sayt that the probability that, given enough time, all tigers in the population will have horizontal stripes is 30% = 0.3.

--------------------------

Available data:

Population size, N = 100 tigers
Number of Tigers with horizontal stripes = 30
Horizontal stripes is caused by an autosomal recessive mutation.

We need to know the probability that all tigers in the population will have horizontal stripes, which is the recessive phenotype.

We assume that the population is in Hardy-Weinberg equilibrium, so there should be no evolution.

Since the population is in H-W equilibrium, the allelic, genotypic and phenotypic frequencies will remain the same generation after generation.

Now, we will calculate the allelic and genotypic frequencies of horizontal striped individuals in the population.

There are 100 individuals, and only 30 have horizontal stripes.

So, the phenotypic frequency, F(HS) is 30/100 = 0.3 = 30%

Since this is a recessive phenotype, this value equals the genotypic frequency, F(hh) = 30%

Finally, we can get the allelic frequency by taking the square root of this value.

F(hh) = q² = 0.3

f(h) = q = √0.3 = 0.55 = 55%

According to these calcs, the probability for the fixation of the recessive allele is 55%, and the probability that all individuals express the recessive horizontal stripes phenotype is 30%.

--------------------------

You can learn more about Hardy-Weinberg equilibrium at

brainly.com/question/12724120?referrer=searchResults

brainly.com/question/9870841?referrer=searchResults

brainly.com/question/419732?referrer=searchResults

brainly.com/question/13603001?referrer=searchResults

brainly.com/question/5028378?referrer=searchResults

6 0

2 years ago

I have another one, please help:(The clown fish is able to make its home in the poisonous sea anenome, but any other fish that c

Anettt [7]

It would be mutualism