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KengaRu [80]
3 years ago
14

Write the equation in standard form then factor the left side of the equation 2x'2+7x=15

Mathematics
2 answers:
Maslowich3 years ago
8 0
The equation in standard form should be 2x^2 + 7x - 15 = 0

Factored the expression is (2x - 3)(x + 5).

In order to find the factored portion, you must look for factors of the front number (2) to use in the front of the parenthesis and factors of the last number (-15) to go in the end. 

When we use the ones that we have above, it distributes to the overall end result. 

(2x - 3)(x + 5)
2x^2 - 3x + 10x - 15
2x^2 + 7x - 15
oksano4ka [1.4K]3 years ago
3 0

given \: equation  -  -  -  > \\  2 {x}^{2}  + 7 x = 15 \\  \\ standard \: form -  -  -  > \\  2 {x}^{2}  + 7x - 15 = 0 \\  \\ factorising \: left \: side -  -  -  >  \\  \\  =  > 2 {x}^{2}  + 7x - 15 \\  \\  =  > 2 {x}^{2}  + 10x - 3x - 15 \\  \\  =  > 2x(x + 5) - 3(x + 5) \\  \\  =  > (x + 5)(2x - 3)
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Simpifly (-5x2 - 3x - 7) + (-2x3 + 6x2 - 8)
ioda

Answer:

-2x³ + x² - 3x - 15

Step-by-step explanation:

Simply combine like terms together:

-5x² - 3x - 7 - 2x³ + 6x² - 8

-2x³ + (-5x² + 6x²) - 3x + (-7 - 8)

-2x³ + x² - 3x + (-7 - 8)

-2x³ + x² - 3x - 15

5 0
3 years ago
Read 2 more answers
The sum of two consecutive integers is 199. Find the integers
Vikki [24]
Here’s your answer. Hope this helped!!

8 0
3 years ago
Solve the simultaneous equation<br> 4x-y=9 <br> 2x-3y= -23
MrMuchimi

Answer:

x = 5

y = 11

Step-by-step explanation:

y = 4x - 9

2x -3(4x - 9) = -23

2x - 12x + 27 = -23

-10x = -23 -27

-10x = -50

minus cancels out

x = 5

y = 4(5) -9

y = 20 - 9

y = 11

4 0
2 years ago
What is the sum of the geometric series
Sergio039 [100]
Answer: 2343 / 256

Explanation

I will do this for you in two forms: 1) adding each term, and 2) using the general formula for the sum of geometric series.

1) Adding the terms:

 4
∑ 3 (3/4)^i = 3 (3/4)^0 + 3 (3/4)^1 + 3 (3/4)^2 + 3 (3/4)^3 + 3 (3/4)^4
i=0

= 3 + 9/4 + 27/16 + 81/64 + 243/256 = [256*3 + 27*16 + 64*9 + 4*81 + 243] / 256 =

= 2343 / 256

2) Using the formula:

n-1
∑ A (r^i) = A [1 - r^(n) ] / [ 1 - r]
i=0

Here n - 1 = 4 => n = 5

r = 3/4

A = 3

Therefore the sum is 3 [ 1 - (3/4)^5 ] / [ 1 - (3/4) ] =

= 3 [ 1 - (3^5) / (4^5) ] / [ 1/4 ] = 3 { [ (4^5) - (3^5) ] / (4^5) } / {1/4} =

= (3 * 781) / (4^5) / (1/4) =  3 * 781 / (4^4) = 2343 / 256

So, no doubt, the answer is 2343 / 256
5 0
3 years ago
Uzanne can work 10 math problems in 15 minutes. How many can she work in an hour and a half?
jeyben [28]
1 and half hour
= 60 minutes+ 30 minutes
= 90 minutes

Now,

Uzanne need 15 minutes to do 10 problems
Uzanne need 1 minute to complete 10/15 problems

Uzanne need 90 minutes to do
= (10/15)*90
=(2/3)*90
=2*30
=60 problems
4 0
3 years ago
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