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Sloan [31]
3 years ago
5

The area of a rectangle is 63 ft^2, and the length of the rectangle is 11 ft more than twice the width. Find the dimensions of t

he rectangle.
Mathematics
1 answer:
Charra [1.4K]3 years ago
5 0
I found someone with the same question as you here is the answer, GOOD LUCK!

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The coordinates of the vertices of a right triangle are (0, 0), (5, 0) and (0, 3). Which of the following statements is true?
Sphinxa [80]
I think A I'm not sure.
7 0
3 years ago
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Find the explicit formula and the type of function
damaskus [11]
Let's examine this, as x increases by 1, what happens to the y-value? The y-value decreases by 2, so the slope is -2. When x = 0, we have our y-intercept, -5. So we can fill in Slope form with the Slope and Y-intercept that the equation is:

y = -2x - 5
4 0
3 years ago
Gordon types 2,964 words in 39 minutes. Find the unit rate.​
atroni [7]

Answer:

76 words per minute

Step-by-step explanation:

2964/39=76 words per minute

8 0
2 years ago
PLEASE HELP ASAP T^T
chubhunter [2.5K]

9514 1404 393

Answer:

  no feasible solutions

Step-by-step explanation:

There are so many inequalities that determining the area covered by all 5 of them is problematic. Hence, we have reversed all of them in the attached graph, so any feasible solution region would remain white. Alas, there is no such region.

This system of inequalities has <em>no feasible solution</em>.

3 0
2 years ago
A walkway goes through the middle of a square playground from one corner to the opposite corner. If the walkway is 20 meters lon
Dahasolnce [82]
I think you would use the Pythagorean Theorem to solve this, as a square cut across diagonally creates two isocele triangles. Since the longest side is 20 m, this value would be imputed into c^2.

a^2 + b^2 = c^2
a^2 + a^2 = 20^2
2a^2 = 400
2a^2/2 = 400/2
a^2 = 200
a = 14.14

Thus, each sides of the playground are 14.14 meters long.

7 0
2 years ago
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