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Aleksandr [31]
3 years ago
15

Need help! Show work

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
8 0
The first step for each of these is adding or subtracting the coefficient to isolate your terms with variables. And then divide to isolate the variable itself.
You might be interested in
If YW bisects XYZ and mZXYW = 25°, then what is mZXYZ?​
Alisiya [41]

Answer:

50°

Step-by-step explanation:

Since, YW bisects angle XYZ.

\therefore m\angle XYZ =2\times m\angle XYW\\\therefore m\angle XYZ =2\times 25\degree \\\huge \purple {\boxed {\therefore m\angle XYZ =50\degree}}

6 0
3 years ago
Can someone help me on these problems and show work
Salsk061 [2.6K]

The simplified expression are as follows;

6mn³ - mn² +  3mn³ + 15mn² =  9mn³ + 14mn²

a⁴b³ + 8a⁴b³  = 9a⁴b³

<h3>How to simplify an expression?</h3>

A simplified expression is express to its lowest term.

Therefore,

6mn³ - mn² +  3mn³ + 15mn²

combine like terms

6mn³  +  3mn³ - mn² + 15mn²

9mn³ + 14mn²

a⁴b³ + 8a⁴b³  = 9a⁴b³

learn more on simplification here: brainly.com/question/403991

#SPJ1

3 0
2 years ago
BRAINLIEST IF YOU HELP the correct simplification of 7x2(6x + 3x2 − 4)? A 21x4 − 42x3 + 28x2 B 42x4 + 21x3 − 3x2 C 21x4 + 42x3 −
exis [7]

\text{Simplify:}\\\\7x^2(6x + 3x^2- 4)\\\\\text{Use the distributive property:}\\\\42x^3+21x^4-28x^2\\\\\text{You can arrange them by exponent}\\\\21x^4+42x^3-28x^2\\\\\text{This means that your answer will be C).} 21x^4 + 42x^3 - 28x^2\\\\\boxed{\text{C).}\,\,21x^4 + 42x^3 - 28x^2}

3 0
3 years ago
A right triangle has a hypotenuse of 70 feet and a leg of 35 feet. What is the length of the other leg? Select one:
saveliy_v [14]
H = 70ft.
P = 35ft.
B = ?

H^2 = P^2 + B^2
70×70 = (35×35) + B^2
B^2 = 4900-1225
B = √3675
B = 35√3 ft.
3 0
3 years ago
A scale drawing of a field is shown below. The drawing uses a scale of 1 in. = 14 ft. What is the area of the actual field?
svp [43]

Answer:

D. 4,704 ft²

Step-by-step explanation:

Giving a scale of 1 in. = 14 ft, to find the actual area of the field represented by the triangular drawing above, convert the length of the base and height to the actual lengths of the field using the scale.

Height of drawing = 8 in.

Actual height = 8*14 = 112 ft

Base of drawing = 6 in.

Actual base = 6*14 = 84 ft

Area of the field = area of ∆

Area = ½*base*height

Area = ½*84*112

Area = 4,704 ft²

3 0
3 years ago
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