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lilavasa [31]
2 years ago
8

Calculate the average time the car took to reach each checkpoint. Record the average time in Table D of your Student Guide. The

average time to the first quarter checkpoint is 2.07 seconds. The average time to the second quarter checkpoint is seconds. The average time to the third quarter checkpoint is seconds. The average time to the finish line is second
Mathematics
1 answer:
zhuklara [117]2 years ago
6 0

The average time the car took to reach each checkpoint are:

  • 2.07
  • 3.16
  • 4.11
  • 4.92

<h3>Average time</h3>

Given:

Time  interval

1              2      3           4

2.02    3.17   4.12    4.93

2.05    3.07  3.98   4.81

2.15    3.25  4.23    5.01

Hence:

First quarter checkpoint

Average time= (2.02 + 2.05 + 2.15) / 3

Average time=6.22/3

Average time= 2.07s

Second quarter checkpoint

Average time= (3.17 +3.07 + 3.25) / 3

Average time=9.49/3

Average time = 3.16 s

Third quarter check point

Average time= (4.12 + 3.98 + 4.23) / 3

Average time=12.33/3

Average time= 4.11 s

Fourth quarter check point

Average time = (4.93 + 4.81 + 5.01) / 3

Average time=14.75/3

Average time= 4.917 s

Average time=4.92s (Approximately)

Therefore the average time the car took to reach each checkpoint are: 2.07, 3.16, 4.11, 4.92.

Learn more about average time here:brainly.com/question/19136062

#SPJ1

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Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

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Step-by-step explanation:

We have the following info given:

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The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

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The confidence interval for the proportion  would be given by this formula

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For the 90% confidence interval the significance is \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution and we got.

z_{\alpha/2}=1.64

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0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131

0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169

And the 90% confidence interval would be given (0.131;0.169).

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