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3 years ago

Make v the subject of the relation KE = ½mv²

Mathematics

2 answers:

VladimirAG [237]3 years ago

8 0

Answer:

v=√(2KE/m)

Step-by-step explanation:

KE=1/2mv^2

2KE=mv^2

(2KE)/m=v^2

sqrt[(2KE)/m]=v

v=√(2KE/m)

Irina18 [472]3 years ago

7 0

Answer:

$v=\sqrt{\frac{2KE}{m} }$

Step-by-step explanation:

$KE = 1/2mv^2$

$KE/1/2=mv^2$

$2KE=mv^2$

$2KE/m=v^2$

$\sqrt{2KE/m} =v$

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ki77a [65]

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3 years ago

Read 2 more answers

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JulijaS [17]

The next three terms are: 1/6 , 0 and -1/6

Step-by-step explanation:

Given sequence is:

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First of all, we have to find the common difference

$here\\a_1 = \frac{5}{6}\\a_2 = \frac{2}{3}\\a_3 = \frac{1}{2}\\a_4 = \frac{1}{3}\\d = a_2-a_1 = \frac{2}{3} -\frac{5}{6} = \frac{4-5}{6} = -\frac{1}{6}\\d = a_3 - a_2 = \frac{1}{2} - \frac{2}{3} = \frac{3-4}{6} = =\frac{1}{6}$

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We can simply add -1/6 to the previous term to find the next terms so,

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The next three terms are: 1/6 , 0 and -1/6

Keywords: Arithmetic sequence, common difference

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3 years ago

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jeyben [28]

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