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Bogdan [553]
3 years ago
6

Which subpart(s) of the 45 cfr 46 is/are sometimes referred to as the common rule?

Mathematics
1 answer:
Olenka [21]3 years ago
8 0

Subpart a is the subpart of the 45 CFR 46 which describes the required protections for all human subjects.

 

The application of the federal policy regarding Human Subjects Protection to 17 Federal agencies and offices is called the Common Rule. Federal agencies that did not sign the agreement (e.g., Department of Labor, etc.) are exempted from the policy. The Common Rule’s main elements include the following:

 

<span>1.     </span>research institutions’ requirements for assuring compliance

<span>2.     </span>obtaining and documenting informed consent requirements for researchers'

<span>3.     </span>Institutional Review Board (IRB) membership, operations, function, record keeping, and review of research requirements

 

 

The specific vulnerable research subjects’ additional protections are included in the Common Rule.

 

 

<span>Additional protections for pregnant women, in vitro fertilization, and fetuses is provided in subpart B.

Additional protections for prisoners is contained in subpart C.</span>

<span>
The same for children is contained in subpart D.</span>

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two arcs of concentric circles are intercepted by the same central angle. the resulting arc length of the arc of the larger circ
Bond [772]
the complete question in the attached figure

Let
A°-----------> <span>the same central angle

</span><span>For the larger circle
length of larger circle=2*pi*r-------> 2*pi*12-----> 75.36 m

360</span>°<span> (full circle) has a length of------------> 75.36 m 
 A</span>°-----------------------------------> 16 m
A°=(16)*360/75.36--------> A=76.43°

For the smaller circle
length of smaller circle=2pi*r-------> 2*pi*7.5-----> 47.1 m

360° (full circle) has a length of------------> 47.1 m 
 76.43°-----------------------------------> X
X=76.43*47.1/360-----> X=10 m ----> length arc of the smaller circle

the answer is
the length arc of the smaller circle is 10 m

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Find the surface area of each figure?Please help
kolbaska11 [484]
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Surface area of the cube
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6(2.5 x 2.5) = 37.5m²

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Surface area of the rectangle prism
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2(11 x 7) + 2(9 x 7) + 2(9 x 11) = 478m²

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2.5 x 2.5 = 6.25m²

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Surface area of the composite figure
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37.5 + 478 - 2(6.25) = 503m²

<em>(* The bottom of the cube and the top of the rectangle prism overlapped, so the area is overlapped twice, minus 2 times of that area)</em>

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Answer: 503m²
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