2(a+bc)=2a+2bc
3.(ab-cb-ba+bc)= 3ab-3cb-3ba+3bc
Since the brackets and multiplication have a higher order than the rest.
Cb=Bc
Ab=ba
Ac=Ca
Because multiplication is commutative.
2a+2bc + cb +ab + ac -(3ab-3cb-3ba+3bc)
2a + 2bc + cb + ab + ac(+ -3ab - - 3cb - -3ba +-3bc)
2a + 2bc + cb + ab + ac -3ab + 3cb + 3ba -3bc
2a + (2bc-3bc +cb + 3cb ) + (ab -3ab + 3ba) + ac
=2a + 3cb + ba+ ac OR 2a +3bc + ab + ac
The Or is just a different way to write it.
Hope this helps
Answer:
8² = 64 < 72 < 9² = 81
Step-by-step explanation:
Hope the above solution will help you
Answer:
A= 1038 in²....
Step-by-step explanation:
There are several ways to find the area of a regular hexagon
In a regular hexagon, split the figure into triangles.
Find the area of one triangle.
Multiply this value by six.
We will apply the formula of area of regular polygon:
A= 1/2r²nsin(360/n)
r = radius
n = number of sides of the regular polygon
We know that,
r= 20 in
n= 6
Now substitute the values in the formula:
A= 1/2(20)²(6)sin(360/6)
A= (20)²(3)sin(360/6)
A= (20)²(3)sin(60)
A=3*(20)² *√3/2
A= 1200 * √3/2
A= 600*√3
A= 1038 in²....
Therefore the approximate area of hexagon is 1038 in²....
X = 7, -3, 2
(x - 7)(x + 3)(x - 2) = 0
(x - 7)(x^2 + x - 6) = 0
x^3 - 6x^2 - 13x + 42 = 0
