The answer is b, -11.
plug in 3 as the input and solve.
The idea is to pair up the terms, factor each sub-group, and then pull out the overall GCF to fully factor.
x^3+5x^2-6x-30
(x^3+5x^2)+(-6x-30)
x^2(x+5)+(-6x-30)
x^2(x+5)-6(x+5)
(x^2-6)(x+5)
-------------
Answer: (x^2-6)(x+5)
Answer:
y = - 3
Step-by-step explanation:
3(-2x+5)=-x-5
-6x+15=-x-5
-5x=-20
x=4
y=-2(4)+5
y=-3
5-2=3 so x is equal to 3
-3+10 is equal to 7 so y is equal to 10
With this we can conclude that x=3 and y=10
I hope that helps :)
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Answer:
![\left[\begin{array}{ccc}0&-1&-2\\0&-3&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-1%26-2%5C%5C0%26-3%265%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The rotation matrix for 90° CCW is ...
![\left[\begin{array}{cc}0&-1\\1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%26-1%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D)
Then the rotated coordinates are ...
![\left[\begin{array}{ccc}0&-1\\1&0\end{array}\right]\cdot\left[\begin{array}{ccc}0&-3&5\\0&1&2\end{array}\right]=\left[\begin{array}{ccc}0&-1&-2\\0&-3&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-1%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-3%265%5C%5C0%261%262%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-1%26-2%5C%5C0%26-3%265%5Cend%7Barray%7D%5Cright%5D)
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The transformation of each ordered pair is ...
(x, y) ⇒ (-y, x)
